Physics of Anti-Gravity Explained in DETAIL... Legendary Video Series!!!, page 4


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reply posted on 1-11-2010 @ 04:04 PM by mbkennel
Originally posted by prepared4truth
reply to
post by loner007



Einstein wasn't respected before he was well known either.

That is the problem with scientific institutions now. They assume that someone that is already well-respected has to come up with plausible theory. But the truth is, new possibilities come from new sources.


Scientific institutions assume that somebody who comes up with a plausible theory already has to understand the existing accepted theory and experiments sufficiently well.


I just finished watching all twelve of these videos and I have to say, well done. I learned a lot from them and I look forward to more. The person who produced these only has a high-school education, yet he can teach physics more easily than most high school teachers these days. Because they're all conventional followers instead of crazy pioneers.


High school teachers are not going to be successful pioneers discovering new fundamental physics.

But they can be crazy.


reply posted on 1-11-2010 @ 04:24 PM by prepared4truth
Originally posted by mbkennel
Originally posted by prepared4truth
reply to
post by loner007



Einstein wasn't respected before he was well known either.

That is the problem with scientific institutions now. They assume that someone that is already well-respected has to come up with plausible theory. But the truth is, new possibilities come from new sources.


Scientific institutions assume that somebody who comes up with a plausible theory already has to understand the existing accepted theory and experiments sufficiently well.


I just finished watching all twelve of these videos and I have to say, well done. I learned a lot from them and I look forward to more. The person who produced these only has a high-school education, yet he can teach physics more easily than most high school teachers these days. Because they're all conventional followers instead of crazy pioneers.


High school teachers are not going to be successful pioneers discovering new fundamental physics.

But they can be crazy.


Did you watch the videos? I think the accepted theory is understood, unless you can somehow prove that it isn't thoroughly explained or stated (which it is).

Also, who are you to say what high school teachers are NOT going to do? Like I said earlier, Einstein was a dropout...



reply posted on 1-11-2010 @ 04:31 PM by prepared4truth
Originally posted by die_another_day
Originally posted by prepared4truth
reply to
post by die_another_day



And oh, you obviously haven't watched the videos. Your post is very close to bordering on "off-topic". Not only does seattle4truth discuss that it's not a 5th force, he states that the pre-existing forces are never tampered with. Their magnetic counterparts are tampered with. Anti-gravity is kind of a misleading term, so I could see how you were thrown off, but next time you should probably look at the videos before commenting on the validity of their claims, or asking questions which were answered within.

He also incorporates EM and super-symmetry. The concept itself is not a conspiracy, obviously. But there may be a conspiracy in the contamination and restraint of materials available to produce "anti-gravity" and "cold fusion". Along with the evidence of "foul play" among the scientific community concerning the results of a pretty simple lab experiment.

Contaminated palladium=contaminated results.
edit on 1-11-2010 by prepared4truth because: address other issues


Actually I was waiting for someone to tell me what I missed.

I simply don't want to spend 2 hrs on a video about a physics conspiracy.

If you think that only the top secret laboratories of the US government can produce "anti-gravity" or "cold fusion" without universities or other countries knowing, then you must be disillusioned.


There is no "anti-gravity,"

There are forces and equal and opposite reactions.



Are you serious? It's not about a physics conspiracy... really, you should watch the videos. Also, why would top secret laboratories of the US government NOT be able to produce "anti-gravity" or "cold fusion" without other universities knowing? How do you know what other countries know? It is a known fact that organizations within countries carry out projects in secret so that other countries do not utilize the tech and they generate propaganda in order to keep people like YOU in the illusion.

Once again, who are you or any person that considers themselves knowledgeable to say, "There is no anti-gravity"? Like I said, if you watch the videos you'd see that "anti-gravity" is not what's being discussed. In better terms, it's "gravido-rotation-inducement".

Stop waiting for someone to tell you something. That's how things get distorted.


reply posted on 1-11-2010 @ 08:25 PM by FalselyFlagged
reply to post by rockn82



The antigravitational field is really gravitomagnetism. It's a purely local field, like how a magnet curves back onto itself.


reply posted on 1-11-2010 @ 08:43 PM by FalselyFlagged
reply to post by zorgon




Gravity manipulation I agree with. Podkletnov used to call it gravity shielding, but that term is WAY WRONG. if it was gravity shielding u could block off the moon and send it out of orbit.

But the antigravitational effects come from a purely local field.

However, its just sementics, gravity manipulation sounds like a bunch of douchebaggery.

Anti-gravitational is a term everyone can understand. "the big bang" isnt technically correct either, since it was tiny as hell, and made no noise.....


But guess what, it's still called the big bang.



reply posted on 1-11-2010 @ 08:44 PM by zorgon
Originally posted by FalselyFlagged
The antigravitational field is really gravitomagnetism. It's a purely local field, like how a magnet curves back onto itself.


This is using a local field



A spinning magnetic field over a stationary magnetic field

But don't forget that the Earth is a dipole magnet itself and rotating. Perhaps that explains why saucers have such erratic flight paths
edit on 1-11-2010 by zorgon because: (no reason given)



reply posted on 1-11-2010 @ 08:53 PM by RedBird
Phew!

Ok, finished the video series. Narrator has a good voice, and doesn't go too fast or to slow.

Everything sounds legit to me (and very cool!), but the devil is (as they say) in the details.

So he starts with this equation: Vt = ƒƛ

Vt = The speed of the quantum transmission
ƒ = The frequency of the emitted photon
ƛ = The wavelength of the photon at the moment of transmission

Now, Frank picks a value of 1.094 x 10^6 m/s for Vt and in the video it is explained where this constant comes from. I believe it was empirically determined.

The point of this equation is that with Vt known, and the frequency of an emitted photon measurable, we can arrive at the wavelength of the photon at the moment of transmission.

Next, he takes a formula describing capacitance between two square plates: C = e0A / D

C = capacitance
e0 = permittivity of free space
A = area
D = distance

He then substitutes ƛ^2 for A, and ƛ/2 for D, resulting in an equation that looks like C = e0ƛ^2 / (ƛ/2). This step seems fishy to me. He's using wavelength as a substitution for distance and area? Maybe this was explained in the video, but if it was, I didn't get it, and I still don't.

This simplifies further to C = 2e0ƛ and since ƛ = Vt / ƒ (as per the first equation, we end up with a formula that looks like this:

C = 2e0Vt / ƒ

If there is funny business going on in his math, it is with regards to this above equation! This just looks like unit manipulation to me. How can capacitance be expressed as a function of frequency at the moment of quantum transmission? Capacitance has nothing to do with the wavelength or frequency of photons. But I'm not a physicist, so what do I know?

Anyways, next we take a formula for energy stored in a capacitor: E = Q^2 / 2C

E = energy
Q = charge (in coulombs)
C = capacitance

He then subs in his 2e0Vt / ƒ in place of C in the denominator, and we arrive at:

E = [Q^2 / 4e0Vt] ƒ


And since Einstein's equation for the photo-electric effect is E = h ƒ

We can isolate [Q^2 / 4e0Vt] = h

Tada!

We've derived Plank's constant as a function of charge squared over speed of quantum transmission.

And just to make sure they're actually equivalent....

Q = 1.60217646 × 10-19 coulombs
Vt = 1.094 x 10^6 m/s
e0 = 8.85418782 × 10-12 m-3 kg-1 s4 A2

(2.56696942 × 10-38) / 4(8.85418782 × 10-12)(1.094 x 10^6) = 6.62513376 × 10-34 m3 kg / s2

Which equals Plank's constant to within significant digits.

So, he's not lying - he does derive plank's constant. But as to whether or not that means anything, or has any relevance, I really have no idea.

I'm not a physicist, I just know how to do algebra. I'll leave it up to the self-described "experts" to explain all this. At least now you can all argue about the actual math, rather than nothing at all.

I mean, seriously, none of the skeptics in this thread so far have even bothered to watch the flippin' video. Now you don't have to. Here's the math. Debunk away.
edit on 1-11-2010 by RedBird because: (no reason given)



reply posted on 1-11-2010 @ 10:12 PM by rockn82
reply to post by FalselyFlagged



Thank you for your answer. However, my question was in more of a rhetorical nature to hopefully get a few people to stop for one moment and think, not necessarily out of the box even. Perhaps this is the perfect equation. Perhaps it is complete crap. But, either way nothing should stop people from investigating the maybes. Flatly disregarding theory or belittling the people who don't think the same as everybody else, gets mankind no where. It was my hope in which some people would have read my post and thought for a moment instead of blurting out "facts", which can change periodically.
It reminds me of the people that go into fits of rage about people attempting to make a "magnet motor". Will it ever work? What are the odds that everybody fails? I am sure the odds are pretty stacked against the inventor. However, if just one person accidentally pops something into the correct alignment and powers a generator which changes the course of humanity, I will be proud of the person that didn't give up.

Good Day All


reply posted on 1-11-2010 @ 10:33 PM by prepared4truth
reply to post by zorgon



Oh yeah, I know Einstein was wrong. Every human makes genuine mistakes. But he was also correct a lot more than he was wrong, at least in the public eye. And he was correct about issues that nobody else could describe.

Also, this doesn't change the fact that he was a dropout. He had his ideas before he got his degree. He taught himself. A formal education isn't always right for people to learn, and does not dictate whether a person is smart. That was my original point.


reply posted on 1-11-2010 @ 11:23 PM by FalselyFlagged
reply to post by prepared4truth



Exactly.

And the truth of the matter is that it DOESN'T MATTER where you went to school, if you can DERIVE PLANCK'S CONSTANT FROM FIRST PRINCIPLES.

Yes, I am shouting. Cause it's that damn revolutionary. LOL
edit on 1-11-2010 by FalselyFlagged because: oops



reply posted on 1-11-2010 @ 11:30 PM by mbkennel
Originally posted by RedBird
Phew!

Everything sounds legit to me (and very cool!), but the devil is (as they say) in the details.

So he starts with this equation: Vt = ƒƛ

Vt = The speed of the quantum transmission
ƒ = The frequency of the emitted photon
ƛ = The wavelength of the photon at the moment of transmission

Now, Frank picks a value of 1.094 x 10^6 m/s for Vt and in the video it is explained where this constant comes from. I believe it was empirically determined.


In actual physics, the velocity of a photon, being a massless particle, is c, which is about 3 x 10^9 m/s.




The point of this equation is that with Vt known,


'known' in the sense of "random baloney pulled from my bellybutton lint"

and the frequency of an emitted photon measurable, we can arrive at the wavelength of the photon at the moment of transmission.

Next, he takes a formula describing capacitance between two square plates: C = e0A / D

C = capacitance
e0 = permittivity of free space
A = area
D = distance

He then substitutes ƛ^2 for A, and ƛ/2 for D, resulting in an equation that looks like C = e0ƛ^2 / (ƛ/2). This step seems fishy to me. He's using wavelength as a substitution for distance and area? Maybe this was explained in the video, but if it was, I didn't get it, and I still don't.


Indeed, because it makes no sense at all.

This simplifies further to C = 2e0ƛ and since ƛ = Vt / ƒ (as per the first equation, we end up with a formula that looks like this:

C = 2e0Vt / ƒ

If there is funny business going on in his math, it is with regards to this above equation! This just looks like unit manipulation to me. How can capacitance be expressed as a function of frequency at the moment of quantum transmission? Capacitance has nothing to do with the wavelength or frequency of photons. But I'm not a physicist, so what do I know?


You know enough to smell bovine scatology.


Anyways, next we take a formula for energy stored in a capacitor: E = Q^2 / 2C

E = energy
Q = charge (in coulombs)
C = capacitance

He then subs in his 2e0Vt / ƒ in place of C in the denominator, and we arrive at:

E = [Q^2 / 4e0Vt] ƒ


And since Einstein's equation for the photo-electric effect is E = h ƒ

We can isolate [Q^2 / 4e0Vt] = h

Tada!

We've derived Plank's constant as a function of charge squared over speed of quantum transmission.


Suppose I discharge the Capacitor Of Eternal Life, so Q = 0. Whoops! Planck constant ain't! There goes quantum mechanics, Newton and Laplace ride again!


I'm not a physicist, I just know how to do algebra. I'll leave it up to the self-described "experts" to explain all this. At least now you can all argue about the actual math, rather than nothing at all.

I mean, seriously, none of the skeptics in this thread so far have even bothered to watch the flippin' video. Now you don't have to. Here's the math. Debunk away.



If you call a tail a leg, how many legs has a dog? Five? No, calling a tail a leg don't make it a leg. --- Abraham Lincoln
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