2+2i=? stasis, one plus imaginary one,
(2+2i)^(2/3)=? Next dimension is within stasis containing the fifth, i.e. 4 & 5
√(2+(2/3i))=? Lapse of 4th and 5th in fourth is 6th
^3√(2+(2/3i))=? 7th in 6th, containing 8th and still in stasis
2+2=? Exit stasis by counter stasis just following the rules, 3rd
This content community relies on user-generated content from our member contributors. The opinions of our members are not those of site ownership who maintains strict editorial agnosticism and simply provides a collaborative venue for free expression.