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In mathematics, it is often useful to view or even define subtraction as a kind of addition, the addition of the additive inverse. We can view 7 − 3 = 4 as the sum of two terms: 7 and -3. This perspective allows us to apply to subtraction all of the familiar rules and nomenclature of addition. Subtraction is not associative or commutative—in fact, it is anticommutative and left-associative—but addition of signed numbers is both.
Originally posted by xxsomexpersonxx
My spin on this:
6÷2(1+2) is the same as 6÷2*(1+2)
2(1+2) is no different than 2*(1+2), just like 2X = 2*X
so 6÷2*(3) = 9
The answer is 9, but it's a simple oversight to cause it to look like one.edit on 2-5-2011 by xxsomexpersonxx because: (no reason given)
Originally posted by grey580
For example: 6÷2×3 = 9, not 1. 6-2+3 = 7, not 1.
Originally posted by Honor93
Originally posted by grey580
For example: 6÷2×3 = 9, not 1. 6-2+3 = 7, not 1.
the sum of the addition within the parenthesis is "ordered" by a multiplier -2 (higher level) and must be performed UPON the sum before division can be properly or sequentially applied.
Rule 1: First perform any calculations inside parentheses.
Rule 2: Next perform all multiplications and divisions, working from left to right.
Rule 3: Lastly, perform all additions and subtractions, working from left to right.
Originally posted by MegaMind
Originally posted by GobbledokTChipeater
Originally posted by MegaMind
Let me ask you what is 1/3 (X + Y) distributed?
x/3 + y/3 correct?
or
(X + Y)/3
or
(X + Y)
Actually, I read it as
1 / (3X + 3Y).
Now you mention it this way, I distinctly remember this problem from my uni text books. If I can find it tomorrow, I will scan the relevant pages up and post.
You are violating the rules with that.
A (B + C) = AB + AC
A = 1/3
therefore,
1/3B + 1/3C
Basic algebra
same as (X + Y)/3 or (B + C)/3edit on 2-5-2011 by MegaMind because: (no reason given)edit on 2-5-2011 by MegaMind because: (no reason given)
Originally posted by MegaMind
reply to post by IamBoon
Simply doesn't matter.
A = 6/2, B = 1, C =2
A (B + C) = AB + BC
6 / 2 (1 + 2) = 9
(1 + 2) is NOT a denominator PERIOD. If it were it would be 6 / (2 (1 + 2)) but it is NOT.
Originally posted by Honor93
in this equation, a=6 b=2(c) and c=(1+2)
try that and see if you get 9
Originally posted by MegaMind
Originally posted by Whatsreal
Is this really still going... the answer is 1... just drop it... the idiots saying 9 are idiots...
DISTRIBUTIVE RULE.... so many people are saying 2(2+1) ..... that the 2 doesn't need to be distributed after doing whats inside the parenthesis???.... well you're wrong, just because you simplified whats in the parenthesis they do not magically disappear.... and you can still distribute the 2 before hand and get the same answer....
6/2(2+1)
6/(2*2 + 1*2)
6/(4+2)
6/(6)
1
please stop confusing the young lad who originally asked the question...
the distributive rule is A (B + C) = AB + AC
therefore,
6 / 2 (1 + 2) = (6/2)1 + (6/2)2 = 9
A = 6/2 --- NOT --- 2
Originally posted by Honor93
please pay attention to what you are writing ... your thought pattern seems to be on the mark but your writing leaves much to be considered.
A does not equal 6/2
a = 6
b = 2 times the sum of c
c= (1+2)
which calculates to the answer 1, only.
Originally posted by MegaMind
Originally posted by knightseifer
but for 6÷2(1+2) , we cannot use 6÷2 as A
Sure you can! "A" can be any damn thing you want!!!
A ( B + C) = AB + ACedit on 2-5-2011 by MegaMind because: (no reason given)
Originally posted by IamBoon
reply to post by MegaMind
I cannot take anyone seriously who says 15y/5y = 3yy.
Originally posted by Honor93
Originally posted by MegaMind
Originally posted by knightseifer
but for 6÷2(1+2) , we cannot use 6÷2 as A
Sure you can! "A" can be any damn thing you want!!!
A ( B + C) = AB + ACedit on 2-5-2011 by MegaMind because: (no reason given)
only in your fantasy land or mind apparently.
a = a .. in this case 6
b = b .. in this case 2
c = c .. in this case (1+2)
if the sum of c times 2 divided by 6 = 9 ... then i need another drink.
Originally posted by IamBoon
reply to post by MegaMind
YOu cannot get rid of y!!!!!!! It doesn't disappear. No matter what y is the equation will ALWAYS be equivalent to 3*y! or 3y!
Originally posted by Honor93
Originally posted by grey580
For example: 6÷2×3 = 9, not 1. 6-2+3 = 7, not 1.
many of us were educated long before the citations of wiki existed ... hint: wiki has been wrong more than once.
for the record, your linear equation of 6/2x3 = 9 does and will always = 9
however, the expression as printed is NOT and i repeat it is NOT a linear problem.
what everyone seems to be overlooking is the fact that although, both division and multiplication are on the same 'level' of processing ... the sum of the addition within the parenthesis is "ordered" by a multiplier -2 (higher level) and must be performed UPON the sum before division can be properly or sequentially applied.
the only Correct answer is "1".