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# 6÷2(1+2)=?

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posted on May, 2 2011 @ 10:36 AM

Simply doesn't matter.

A = 6/2, B = 1, C =2

A (B + C) = AB + BC

6 / 2 (1 + 2) = 9

(1 + 2) is NOT a denominator PERIOD. If it were it would be 6 / (2 (1 + 2)) but it is NOT.

posted on May, 2 2011 @ 10:38 AM

Originally posted by GobbledokTChipeater

Originally posted by MegaMind

"A" can be any damn thing you want it to be!!!

Yes and if you want it to be 1/3, then you should write (1/3). Otherwise A is taken to mean the number directly before the brackets.

Wrong!!!!

1 / A (B + C) = (1/A)B + (1/A)C, NOT AB + AC.
edit on 2-5-2011 by MegaMind because: (no reason given)

posted on May, 2 2011 @ 10:40 AM

Originally posted by MegaMind

Simply doesn't matter.

A = 6/2, B = 1, C =2

A (B + C) = AB + BC

6 / 2 (1 + 2) = 9

(1 + 2) is NOT a denominator PERIOD. If it were it would be 6 / (2 (1 + 2)) but it is NOT.

Using your logic I could say that 6/2 is NOT a fraction PERIOD. If it were it would be written as (6/2)(1+2). And I agree.

posted on May, 2 2011 @ 10:40 AM

Originally posted by MegaMind

Originally posted by knightseifer

Mate, 1/(3B+3C) cant be written as 1/3B + 1/3C

No kidding, but I didn't write that did I?

1/3(B + C) = B/3 + C/3 or 1/3B + 1/3C

A ( B + C) = AB + BC

"A" can be any damn thing you want it to be!!!

You people pass algebra???
edit on 2-5-2011 by MegaMind because: (no reason given)

edit on 2-5-2011 by MegaMind because: (no reason given)

Sorry mate, it was my problem with my eyes..
In your case, 6÷2x(1+2) or 6(1+2)÷2 or (6÷2)*(1+2)

but the question in this problem is different, it is 6÷2(1+2) where numerator is 6 and denominator is 2(1+2)

posted on May, 2 2011 @ 10:43 AM
Guys, what is 15y ÷ 5y ?
Did you get 3 or 3y^2 ?

If your answer was 9 in previous question, you should get 3y^2 because
15y (÷) 5y
= 15 (x) y (÷) 5 (x) y
= 15y (÷) 5 (x) y
= 3y (x) y
= 3y^2

*(x) = multiply, (÷) = divide

posted on May, 2 2011 @ 10:47 AM

Originally posted by knightseifer
Guys, what is 15y ÷ 5y ?
Did you get 3 or 3y^2 ?

If your answer was 9 in previous question, you should get 3y^2 because
15y ÷ 5y = 15 x y ÷ 5 x y
= 15y ÷ 5 x y
= 3y x y
= 3y^2

What if you got answer 1 for previous question?
15y ÷ 5y = 15y/5y
= 3

So, back to the question 6÷2(1+2)=?

Let x = (1+2) = 3 -------------eq 1

6÷2x = 3/x

Put eq 1 into 3/x, you get
3/3 = 1

That is the best way of explaining it yet.

posted on May, 2 2011 @ 10:48 AM

Originally posted by knightseifer
15y ÷ 5y = 15 x y ÷ 5 x y
= 15y ÷ 5 x y
= 3y x y
= 3y^2

15 x y ÷ 5 x y != 15 y ÷ 5 x y

and

15y ÷ 5y = 3

15y
------ = 3
5y

15y is 3 times bigger than 5y!!

edit on 2-5-2011 by MegaMind because: (no reason given)

edit on 2-5-2011 by MegaMind because: (no reason given)

posted on May, 2 2011 @ 10:50 AM

Originally posted by knightseifer
Guys, what is 15y ÷ 5y ?
Did you get 3 or 3y^2 ?

If your answer was 9 in previous question, you should get 3y^2 because
15y ÷ 5y = 15 x y ÷ 5 x y
= 15y ÷ 5 x y
= 3y x y
= 3y^2

What if you got answer 1 for previous question?
15y ÷ 5y = 15y/5y
= 3

So, back to the question 6÷2(1+2)=?

Let x = (1+2) = 3 -------------eq 1

6÷2x = 3/x

Put eq 1 into 3/x, you get
3/3 = 1
edit on 2-5-2011 by knightseifer because: (no reason given)

15y ÷ 5y

The way you have it written it seems obvious that you want it interpreted as:

15*y
------
5*y

However if you follow the rules of a linear equation such as the one you have written, technically you would need parentheses to denote what is in the denominator.

15 x y ÷5 x y Interpreted linearly is technically

15*y
-------- * y
5

which would be 3yy or 3(y^2)

It is obvious what you are attempting to write, but technically parentheses are required to put the 5y in the denominator.

posted on May, 2 2011 @ 10:52 AM

Originally posted by MegaMind

15 x y ÷ 5 x y != 15 y ÷ 5 x y

Exactly! Much the same as

6÷2(1+2) != 6÷2*(1+2).

posted on May, 2 2011 @ 10:54 AM

Originally posted by GobbledokTChipeater

Originally posted by MegaMind

15 x y ÷ 5 x y != 15 y ÷ 5 x y

Exactly! Much the same as

6÷2(1+2) != 6÷2*(1+2).

Complete and utter nonsense. Tell me what level of math are you educated to?

posted on May, 2 2011 @ 10:55 AM
youtu.be...

I couldn't get it to embed properly... sorry

posted on May, 2 2011 @ 10:55 AM

Originally posted by ASeeker343

Originally posted by knightseifer
Guys, what is 15y ÷ 5y ?
Did you get 3 or 3y^2 ?

If your answer was 9 in previous question, you should get 3y^2 because
15y ÷ 5y = 15 x y ÷ 5 x y
= 15y ÷ 5 x y
= 3y x y
= 3y^2

What if you got answer 1 for previous question?
15y ÷ 5y = 15y/5y
= 3

So, back to the question 6÷2(1+2)=?

Let x = (1+2) = 3 -------------eq 1

6÷2x = 3/x

Put eq 1 into 3/x, you get
3/3 = 1
edit on 2-5-2011 by knightseifer because: (no reason given)

15y ÷ 5y

The way you have it written it seems obvious that you want it interpreted as:

15*y
------
5*y

However if you follow the rules of a linear equation such as the one you have written, technically you would need parentheses to denote what is in the denominator.

15 x y ÷5 x y Interpreted linearly is technically

15*y
-------- * y
5

which would be 3yy or 3(y^2)

It is obvious what you are attempting to write, but technically parentheses are required to put the 5y in the denominator.

posted on May, 2 2011 @ 10:57 AM

Sorry you are using x as the * instead as x as a variable. see notation is the problem. on a computer the symbols are /, *, +, -

an x is frequently a variable. I haven't used an "x" as a multiplication symbol since elementary school.

a dot, parenthesis next to numbers or variables and *, which is the computer form of a multiplication dot, are all multiplication.
edit on 2-5-2011 by MegaMind because: (no reason given)

posted on May, 2 2011 @ 11:00 AM

Originally posted by MegaMind

Complete and utter nonsense. Tell me what level of math are you educated to?

This is a discussion, not a # measuring contest.

.
edit on 2/5/11 by GobbledokTChipeater because: (no reason given)

posted on May, 2 2011 @ 11:01 AM

Originally posted by MegaMind

Originally posted by knightseifer
15y ÷ 5y = 15 x y ÷ 5 x y
= 15y ÷ 5 x y
= 3y x y
= 3y^2

15 x y ÷ 5 x y != 15 y ÷ 5 x y

and

15y ÷ 5y = 3

15y
------ = 3
5y

15y is 3 times bigger than 5y!!

edit on 2-5-2011 by MegaMind because: (no reason given)

edit on 2-5-2011 by MegaMind because: (no reason given)

Answer would be 3y and that is not a solvable equation. Only one taht can be simplified.

posted on May, 2 2011 @ 11:03 AM

Originally posted by knightseifer

Ok ill bite.

The way you have it written it is obvious you want it interpreted as

15*y
-------
5*y

Which simplifies to 3.

Your given equation however, simplified linearly = 15*y÷5*y
this simplifies to 3*y*y >> 3yy

When writing 15y ÷ 5y it is commonly assumed that 5y is the denominator, even though it technically needs parentheses. This logic should NOT be applied to the OP's question

6÷2(2+1)

In this case the answer is 3(3) = 9

posted on May, 2 2011 @ 11:03 AM

fine but it is actually relevant. You wouldn't be arguing your points the way you are otherwise ...

posted on May, 2 2011 @ 11:05 AM

Simplified it is just 3y. Not 3yy or anything else.... just 3y. It is also a problem that cannot be solved just simplified.

posted on May, 2 2011 @ 11:07 AM

Originally posted by IamBoon

Originally posted by MegaMind

Originally posted by knightseifer
15y ÷ 5y = 15 x y ÷ 5 x y
= 15y ÷ 5 x y
= 3y x y
= 3y^2

15 x y ÷ 5 x y != 15 y ÷ 5 x y

and

15y ÷ 5y = 3

15y
------ = 3
5y

15y is 3 times bigger than 5y!!

edit on 2-5-2011 by MegaMind because: (no reason given)

edit on 2-5-2011 by MegaMind because: (no reason given)

Answer would be 3y and that is not a solvable equation. Only one taht can be simplified.

Wrong, simply wrong! y ÷ y = 1.

(15 * y) ÷ (5 * y) = 3. The "y"s "cancel each other out"

15 * y
------- = 3
5 * y
edit on 2-5-2011 by MegaMind because: (no reason given)

edit on 2-5-2011 by MegaMind because: (no reason given)

posted on May, 2 2011 @ 11:08 AM

Originally posted by IamBoon

Simplified it is just 3y. Not 3yy or anything else.... just 3y. It is also a problem that cannot be solved just simplified.

How do you get 3y??

There are 2 y's. Depending on how you write it they need to multiply or cancel, but you cant just throw one out. And yes its not a true equation, just an expression to be simplified. But so is the original question posed by the OP

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