It looks like you're using an Ad Blocker.
Please white-list or disable AboveTopSecret.com in your ad-blocking tool.
Thank you.
Some features of ATS will be disabled while you continue to use an ad-blocker.
Originally posted by MegaMind
No the equation is not changed at all 6/2 (1+2) = 6(1+2)/2 they are equivalent.
In fact these are all equal
6/2(1+2) = 6(1+2)/2 = 6/2 + 12/2 = 6(1/2 + 2/2) = (6 + 12)/2 = 9
Originally posted by Honor93
Originally posted by MegaMind
No the equation is not changed at all 6/2 (1+2) = 6(1+2)/2 they are equivalent.
In fact these are all equal
6/2(1+2) = 6(1+2)/2 = 6/2 + 12/2 = 6(1/2 + 2/2) = (6 + 12)/2 = 9
NO, they are not equivalent ... nice try though.
6/2(1+2) = 1
whereas each of these do equal 9
6(1+2)/2 = 9
6/2+12/2 = 9
6(1/2+2/2) = 9
(6+12)/2 = 9
you must complete the orders by level ... what you suggest breaks all the rules by applying division over a subset ordered to be multiplied ... that is a no go.
Rule 1: First perform any calculations inside parentheses.
Rule 2: Next perform all multiplications and divisions, working from left to right.
Rule 3: Lastly, perform all additions and subtractions, working from left to right.
Originally posted by MegaMind
Originally posted by IamBoon
reply to post by MegaMind
YOu cannot get rid of y!!!!!!! It doesn't disappear. No matter what y is the equation will ALWAYS be equivalent to 3*y! or 3y!
Go back to your school and demand a refund!
15 * y
--------- = 3
5 * y
"y"s canceledit on 2-5-2011 by MegaMind because: (no reason given)edit on 2-5-2011 by MegaMind because: (no reason given)
Originally posted by MegaMind
and when ever you see 3 (Y + 1) it is really 3 * (Y + 1) or 3 * Y + 3
stick to those rules and there will never be a problem interpreting.
and when ever you see 3 (Y + 1) it is really 3 * (Y + 1) or 3 * Y + 3
Originally posted by MegaMind
Originally posted by Honor93
Originally posted by grey580
For example: 6÷2×3 = 9, not 1. 6-2+3 = 7, not 1.
the sum of the addition within the parenthesis is "ordered" by a multiplier -2 (higher level) and must be performed UPON the sum before division can be properly or sequentially applied.
Simply not true. No such thing. Convention must be accepted. Here is the convention.
www.mathgoodies.com...
Rule 1: First perform any calculations inside parentheses.
Rule 2: Next perform all multiplications and divisions, working from left to right.
Rule 3: Lastly, perform all additions and subtractions, working from left to right.
Like I said 6 * (1/2) * (1+2) = 9
rule 1: 6 / 2 (3)
rule 2: 3 * 3
edit on 2-5-2011 by MegaMind because: (no reason given)
mathgoodies is useful if you attend elementary school but that's about it.
Originally posted by MegaMind
reply to post by Honor93
A (B + C) = AB + AC
1 / 3 (B + C) = (1/3)B + (1/3)C
is that clear? what don't u get? A = 1/3, or 6/2 or whatever the hell else you want it to be.
edit on 2-5-2011 by MegaMind because: (no reason given)
Originally posted by MegaMind
Originally posted by Honor93
in this equation, a=6 b=2(c) and c=(1+2)
try that and see if you get 9
This statement you made above about the equation A (B+C) = AB + AC and 6 / 2 (1 + 2) clearly shows you do not have even a basic grasp of algebra.edit on 2-5-2011 by MegaMind because: (no reason given)edit on 2-5-2011 by MegaMind because: (no reason given)
Originally posted by MegaMind
A (B + C) = AB + AC
according to your substitution from above the eq yields.
6 (2 * (1+2) + (1+2)) This is just garbage.
the correct substitutions for the equation are
A = 6/2 (a fraction get over it)
B = 1
C = 2
6 / 2 (1 + 2)
Originally posted by MegaMind
If standard notation applies this would generally be interpreted as (15 * y) / (5 * y) = 3
Originally posted by Honor93
Originally posted by MegaMind
If standard notation applies this would generally be interpreted as (15 * y) / (5 * y) = 3
actually, this clarifies your ignorance for me, thanks.
only in an instruction manual will you see such nonsense ... in the adult/real world, it's written 15y/5y=x, solve for x.
which cycles right back to 2(1+2) = 6 which is then divided by A (or 6) resulting in the answer yet again of "1"
Originally posted by MegaMind
Originally posted by Honor93
Originally posted by MegaMind
No the equation is not changed at all 6/2 (1+2) = 6(1+2)/2 they are equivalent.
In fact these are all equal
6/2(1+2) = 6(1+2)/2 = 6/2 + 12/2 = 6(1/2 + 2/2) = (6 + 12)/2 = 9
NO, they are not equivalent ... nice try though.
6/2(1+2) = 1
whereas each of these do equal 9
6(1+2)/2 = 9
6/2+12/2 = 9
6(1/2+2/2) = 9
(6+12)/2 = 9
you must complete the orders by level ... what you suggest breaks all the rules by applying division over a subset ordered to be multiplied ... that is a no go.
Then go tell these people www.mathgoodies.com...
that their rules are no good you know better.
Rule 1: First perform any calculations inside parentheses.
Rule 2: Next perform all multiplications and divisions, working from left to right.
Rule 3: Lastly, perform all additions and subtractions, working from left to right.
There is no "level" or "subset". You are simply lost .... God I hope you don't work in education - esp MATH.edit on 2-5-2011 by MegaMind because: (no reason given)
Every student learns “the” distributive law at an early age:
Right 3(x + 7) = 3(x) + 3(7).
In fact there are many distributive laws, for instance
Right (3x)² = 3² x²
Unfortunately, many students also learn all sorts of other distributions that are invalid, like “expanding”
(x − 6)² = x² − 6² WRONG!
Bad habits like that one seem to stick to students like, like, ... well, like unwanted sticky things.
A simple rule can help you remember how you can combine operations and how you cannot — which distributions are legal and which are illegal.
The Solution
Think of a small house. It’s got a basement, a ground floor, and an attic. You can’t jump right from the basement to the attic, can you? But you can take stairs between the basement and ground floor, or between the ground floor and the attic.
You combine operations just like that. If the operations are on adjacent levels, you can combine them; otherwise you can’t. What are the levels? Forget PEMDAS; there are really only three operations to be concerned with:
house floors ~~ operations
attic ~~ powers and roots
ground floor ~~ multiply and divide
basement ~~ add and subtract
And the rule is very simple:
You can distribute any operation over an operation one level below it. There are no other distributions.
Originally posted by MegaMind
reply to post by Honor93
I see that in addition to math you have a reading comprehension problem. I'm not getting paid to tutor here. Can or did you even read those rules? Do you know what they say and how to apply them to 6 / 2 (1 + 2)?edit on 2-5-2011 by MegaMind because: (no reason given)
mathgoodies is useful if you attend elementary school but that's about it.
yeah its pretty basic hard to believe you don't get it.edit on 2-5-2011 by MegaMind because: (no reason given)
Originally posted by MegaMind
reply to post by Honor93
Like I said to the other guy - Go back to your school and demand a refund. You haven't got the first clue about algebra. I'm out and this time for good
Originally posted by Honor93
try this link on for size: oakroadsystems.com...
Every student learns “the” distributive law at an early age:
Right 3(x + 7) = 3(x) + 3(7).
No fear dear, my patience for dealing with students such as yourself wore out many years ago ... i tutor those who WANT help, not force feed those who think they know better.