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Originally posted by buddhasystem
By the time your brain starts melting down, you know you are probably using natural units
In mechanics, I did the most in metric units, actually. I forget what Jackson used in his book, it's been a while.
Originally posted by Mary Rose
Originally posted by Bobathon
. . . in reality the strong force is not powerful enough to overcome the electrostatic force between two protons.
Please explain the significance of the above as it fits in to the argument about the comparison of the mass of the two types of proton and your alleged Haramein math errors in general.
What, if anything, are you saying about the strong force of the standard model?
Why did you link to the Wikipedia article on "Diproton," which the article says is a hypothetical type of helium nucleus consisting of two protons and no neutrons?
Originally posted by Bobathon
Where it fits in: from Haramein's paper, in his equation (14) he gives the electrostatic force (or Coulomb repulsion) as 3.3 x 10^6 dynes, and his postulated alternative to the strong force as 7.49x10^47 dynes.
Originally posted by Mary Rose
Originally posted by Bobathon
Where it fits in: from Haramein's paper, in his equation (14) he gives the electrostatic force (or Coulomb repulsion) as 3.3 x 10^6 dynes, and his postulated alternative to the strong force as 7.49x10^47 dynes.
So, in essence, you're saying that the strong force of Haramein's paper is the same as the strong force of a diproton, which is hypothetical and doesn't exist in nature?
And in essence, you're saying that the strong force in the standard model is not as Haramein represents it in his paper?
Originally posted by Bobathon
Therefore the strong force of Haramein's paper is wrong.
Originally posted by Mary Rose
Originally posted by Bobathon
Therefore the strong force of Haramein's paper is wrong.
To be clear, "the strong force" in the above is Haramein's postulate for a replacement for the strong force of the standard model, and you're basing this, at least in part, on the information you provided about the Diproton?
Originally posted by Bobathon
The diproton isn't something invented by the Standard Model, it's a clear, unambiguous observational fact that they do not exist because they do not hold together.
Originally posted by Mary Rose
Originally posted by Bobathon
The diproton isn't something invented by the Standard Model, it's a clear, unambiguous observational fact that they do not exist because they do not hold together.
So because the diproton doesn't exist, two Schwarzschild protons don't exist?
The list of observational evidence which contradicts the Schwarzschild proton is long, that's just one item on the list.
Originally posted by Mary Rose
Originally posted by Bobathon
The diproton isn't something invented by the Standard Model, it's a clear, unambiguous observational fact that they do not exist because they do not hold together.
So because the diproton doesn't exist, two Schwarzschild protons don't exist?
So one person tells you they don't know the source for the strong force but can make good predictions with their model, in spite of not knowing the source.
Originally posted by Mary Rose
In this post, I asked about the issue that a source for the strong force is not specified in the standard model.
The response I got, was "I don't know what a source for the strong force actually means, to be honest. What does a 'source' mean?"
Originally posted by Bobathon
Originally posted by Mary Rose
Originally posted by Bobathon
. . . in reality the strong force is not powerful enough to overcome the electrostatic force between two protons.
Please explain the significance of the above as it fits in to the argument about the comparison of the mass of the two types of proton and your alleged Haramein math errors in general.
What, if anything, are you saying about the strong force of the standard model?
Why did you link to the Wikipedia article on "Diproton," which the article says is a hypothetical type of helium nucleus consisting of two protons and no neutrons?
The diproton doesn't exist in nature, because in this simplest configuration of two protons, the electrostatic force pushing them apart is stronger than the strong force pulling them together.
Where it fits in: from Haramein's paper, in his equation (14) he gives the electrostatic force (or Coulomb repulsion) as 3.3 x 10^6 dynes, and his postulated alternative to the strong force as 7.49x10^47 dynes.
As you can see, if you understand these numbers, his alternative to the strong force pulling them together is 227,000,000,000,000,000,000,000,000,000,000,000,000,000 times bigger than the electrostatic force pushing them apart.
You see the problem?
Originally posted by micpsi
This is incorrect. The diproton is unstable not because the Coulomb force is stronger than the strong force (it is not) but because the magnitude of the strong force between two nucleons depends on the direction of their spins, and the Pauli Exclusion Principle requires the two protons to have anti-parallel spins, for which spin state the spin-spin interaction results in a strong force that is too weak to bind the two protons together.
Originally posted by Mary Rose
In this post, I asked about the issue that a source for the strong force is not specified in the standard model.
The response I got, was "I don't know what a source for the strong force actually means, to be honest. What does a 'source' mean?"
I see a fundamentally different approach illustrated here. My interest in Haramein's work relates to his quest to understand the origin of things, and the criticism that has come from other members seems to relate to not even relating to the question from the get-go. Like it's not important.
If you're not interested in the origin of mass, you're not going to be interested in a theory that derives mass from vacuum energies (as well as unifying gravity to the quantum world).
Different people have different perspectives.
Three very basic points:
Originally posted by Mary Rose
If you're not interested in the origin of mass, you're not going to be interested in a theory that derives mass from vacuum energies (as well as unifying gravity to the quantum world).
Originally posted by micpsi
This is incorrect. The diproton is unstable not because the Coulomb force is stronger than the strong force (it is not) but because the magnitude of the strong force between two nucleons depends on the direction of their spins, and the Pauli Exclusion Principle requires the two protons to have anti-parallel spins, for which spin state the spin-spin interaction results in a strong force that is too weak to bind the two protons together.
Did one of your cohorts write that?
CERN Ask an Expert Service responded : "The deuteron (one proton plus one neutron) has angular momentum (spin) of one unit. The proton and neutron are in a state of zero orbital angular momentum with their spins (of 1/2) aligned. If we replaced the proton by another neutron, we would have two identical fermions (neutrons) in exactly the same state. This is not allowed by the 'Pauli exclusion principle'." > Question: Since proton and neutron form stable deuteron, Why dont 2 > neutrons bind with the strong nuclear force ?