Will it take off?, page 1
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reply posted on 13-2-2006 @ 03:33 PM by dragon72
It will take off.

The thing to remember is that the wheels aren't directly connected to the propulsion system. They're essentially frictionless meaning what happens to them has no effect on what happens to the rest of the plane.

Think of it this way. Say the plane is moving forwards at 100kph. That means the conveyer is moving 100kph in the opposite direction. The wheels would move at what would feel like to them to be 200kph. Because the wheels are frictionless there is no effect on the plane itself. To the wheels there is no difference between this situation and the plane travelling at 200kph on a fixed ground. The wheels in this situation only support the weight of the plane, they have no effect on the forces in the x direction. It's as if they weren't even there. In fact it doesn't matter what speed the conveyer is travelling at.



From my picture above the plane is providing force in one direction from the engines. The conveyor is providing force in the other direction and because the wheels are frictionless there's no connection between the two.

In reality there is some friction in the wheels so if the conveyer is travelling at 100kph the plane is travelling forwards at 90kph. It would make the beginning (low speed) difficult but at takeoff speed the effect would be negligible.

It does get confusing and is very counter intuitive but once you realise that a planes wheels don't provide the propulsive force like a car it starts to make sense.

P.S. ph34r my l33t dr4w1ng sk1llz


reply posted on 13-2-2006 @ 11:18 PM by Bhadhidar
As stated before "take-off" is dependent upon lift. Lift is generated by the Bernoulli Effect resulting from air moving at higher speed over the top of the wing; thus creating an area of lower pressure Above the wing. the relatively higher pressure under the wing thus "lifts" the plane into the air.

Thrust, provided either by a propeller or jet exhaust, serves to push the wing through the ambient air at the speed required to generate sufficient lift.

If a sufficient volume of air does not flow around the airfoil of the wing with sufficient velocity (ie.: take-off speed), there will not be suffiecient lift generated to allow the plane to fly.

Speed is measurement of velocity relative to another object, generally speaking, that object is the ground. Which, although the Earth (the "ground" in this case) spins at some 3000 MPH, I believe, is generally perceived of as being stationary (Except sometimes in California!).

In the thought excercise given, the forward velocity of the plane is exactly countered by the "treadmill runway" thus negating the forward velocity of the plane. The plane would have the same velocity, therfore , if its wheels were locked and unmoving.

Consider: A plane, when parked on the runway is still "moving" at close to 3000 MPH due solely to the spin of the planet it's parked on; yet it is not airborn. Why not? Because it's Relative velocity to the surrounding air, which is Also moving at the same relative speed as the ground, and therefore, to the plane parked on the ground, is 0 MPH.

Depite the vast volume of air (the entire atmosphre) available, the failure of that volume, no matter how vast, to flow about the plane's wings to generate lift will leave the plane earth-bound.

The plane's engines do not generate lift; they generate thrust, which is translated into velocity relative to environment, which results in lift. No matter how much thrust an engine produces (nor the means by which it produces said thrust), if there is no Velocity (or if that velocity is countered in some way, say by a moving runway) there will be no Lift.

As a "backwards" example consider what can happen to a plane, parked on a airport tarmac, in a high wind.

A large volume of air, at sufficient velocity (no engines involved, no forward speed on the part of the plane) and yet the hapless, pilotless plane becomes disaterously airborn.
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