Here's what I have so far:
With (mostly, missing right margin) the whole cipher, I was able to get a much more accurate frequency count. Here's where you guys can help. *HELP
WANTED* The letters E, T, A, O, N, I, S, and H are the top 8 recurring letters in the english language. It's a matter of matching those letters to
my (mostly accurate) frequency count. I am deducing that the cipher can be translated into english, as it has a "Templarish" feel to it. Out of the
english alphabet, with coding it, he left out 6 letters, B, D, G, N, W, and Z. That may be a clue as well.
There are 19 Letters used, 16 unique Symbols, and 9 base Numbers, for a total of 44 unique characters. There is either some redundancy going on, or
some characters may have "word" meanings. 44 is a large alphabet to work with. *HELP WANTED* Let me explain the Frequency Count.
In any language which is based upon an alphabet, there is a certain number of letters to be used. The alphabet consists of the smallest mutually
accepted "idiograms". There have been thousands of such alphabets devised. Be thankful you're not Japanese, because they have over 108 basic
"ideograms". Very complicated.
Any alphabet has to "recycle" the letters to form different "words", in order to produce anything mutually acceptable between the members of the
community speaking that language. However, certain letters appear more often. I counted them, and am sorting through the mound of data I derived.
There are three sets of "ideograms", one of Letters, one of Symbols, and one of Numbers. Here's the list, and I listed them (cipher symbol) = freq.
count.
Numbers:
(1)=20 [may also be an "I"]
(2)=11
(3)=66
(4)=37
(5)=73
(6)=21
(7)=40
(8)=60
(9)=28
Symbols:
(large "Cross")=35
(small "cross")=12
("i" symbol)=5
("dotted W")=1
(i)=16
(ii)=22
(iii)=46
( : )=190
(.)=13
(=)=93
(-)=25
(%)=28
(oo)=28
(#)=26
("backwards Epsilon")=1
("lowercase d")=8
(ooo)=22
Letters:
(a)=3
(c)=4
(e)=2
(f)=2
(h)=5
(i)=20
(j)=5
(k)=6
(l)=3
(m)=1
(o)=? maybe "zero"
(p)=9
(q)=1
(r)=31
(s)=7
(t)=1
(v)=5
(x)=1 maybe y
(y)=15
So here is where the *HELP WANTED* sign comes in.
I have a summary, check the numbers, but numbers (5), (3), (8), and (4) are favored the most. Symbols are ( : ), (=), and (iii), with the letters
being (r), (y), and (i). That's ten common characters in this cipher. My etaonish list is 8, so the possibility of matching the most common english
letters to the most common elements is good. The correlation is a good place to start.
The portion to the bottom left looks like it needs a different key, but if we can figure out the first, we can figure out the second. I started
middle left, at that sequence number 1-9. I also tried the little section above that. My key was (5)=e, (3)=s, (8)=n, (iii)=a, (=)=t, and (r)=s.
You guys can substitute any letters for any symbols, this is just a good place to start. That key isn't totally accurate.
Using that key, starting middle left, going down:
a_t_nt_ _n_ _t
_t_o:t_ _ _ _
*templarish crosses x2*
o_n:e
_ _n:t:
_ _n:s:e:_
_ _s:nt_ _t
_ _n:t:
_ _nt_:_:_
_ _o:ts_t:__
n_nt_ _ _so_
_:_:_
*templarish crosses x2*
Of course, I am going to play with different values, and see if something doesn't start to appear. I havn't even tried yet to address other
"interesting sections", but I wanted to post how far I've gotten so far.
If you find the key, be sure to post it!
edit on 3/19/11 by Druid42 because:
renders as a smiley face, lol, added spaces.
edit on 3/19/11 by Druid42 because:
another smiley, lol