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Originally posted by spy66
The mass of the coin is not equal all around. That means your equation would only work in a vacuum? The force up is not equal to the force down with normal G.
Since there are only two sides to a coin. Its logic that a even number would be the right answer. There are only two possibilities.
But how would you know beforehand which side the coin would land on before you tossed it?
Your equation does not tell you that.
[edit on 27.06.08 by spy66]
Originally posted by Gentill Abdulla
Originally posted by spy66
The mass of the coin is not equal all around. That means your equation would only work in a vacuum? The force up is not equal to the force down with normal G.
Since there are only two sides to a coin. Its logic that a even number would be the right answer. There are only two possibilities.
But how would you know beforehand which side the coin would land on before you tossed it?
Your equation does not tell you that.
[edit on 27.06.08 by spy66]
It doesn't tell you unless you always know how much force is applied.
Since weight is only the amount of pull gravity has on an object which mass weight can substitute for mass.
You forget it landing on its edge. That's a third possibility.
Originally posted by harrytuttle
Nice equation, but how are you going to know what the inputs are between the time the person begins the flip and when it's caught?
The answer is, you won't. So there goes your dream of 100% predictable coin tosses.
It's better to just have a double head coin.
Originally posted by spy66
If it lands on the edge, it still need to flip to one side. That has to be added to your equation. Because your equation is not complete until the coin shows heads or tail.
Originally posted by valhala
reply to post by Phlynx
Give me all input variables you think we need and I'll write a proggy
Originally posted by Gentill Abdulla
Originally posted by spy66
Originally posted by Gentill Abdulla
Originally posted by spy66
The mass of the coin is not equal all around. That means your equation would only work in a vacuum? The force up is not equal to the force down with normal G.
Since there are only two sides to a coin. Its logic that a even number would be the right answer. There are only two possibilities.
But how would you know beforehand which side the coin would land on before you tossed it?
Your equation does not tell you that.
[edit on 27.06.08 by spy66]
It doesn't tell you unless you always know how much force is applied.
Since weight is only the amount of pull gravity has on an object which mass weight can substitute for mass.
You forget it landing on its edge. That's a third possibility.
If it lands on the edge, it still need to flip to one side. That has to be added to your equation. Because your equation is not complete until the coin shows heads or tail.
By landing on its edge I mean like this...
Heads Tails
_____ _____ Edge l
Originally posted by spy66
That edge also has two sides. That are a bit smaller then the edge you refer to. The odds for the coin to land on the edge of the edge is larger, because of the size of that side of the coin, and because of rotation(Momentum).
Originally posted by TheRealJesus
So your saying no one can pass the speed of light? I already did.
Originally posted by Gentill Abdulla
Originally posted by spy66
That edge also has two sides. That are a bit smaller then the edge you refer to. The odds for the coin to land on the edge of the edge is larger, because of the size of that side of the coin, and because of rotation(Momentum).
But it is still a possibility is it not?
(I think we should stop with the long quotes. You and me)
Originally posted by spy66
Your equation is right if you either want heads or tails. If the coin shows heads before you toss it. And you want heads to show when it lands. The coin must flip a even number.
The third side doesn't count since it wasn't a part of the experiment.
Originally posted by spy66
reply to post by Gentill Abdulla
You have to count the fall as a rotation.
If a coin rotates half way, Its between two sides. If it lands on the edge and falls down it will complete the rotation, It wont matter what side it falls down on. It will complete a rotation either way?
Originally posted by Sinter Klaas
Who really likes to know anyway ?
When I flip a coin it is to let faith decide.
IMO the only ones that want to know, are the ones that plan to cheat.