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Originally posted by Sinter Klaas
reply to post by Gentill Abdulla
I've noticed you wonder a lot. Keep that up
Never once mentioned you cheat. It seemed kind of impossible while doing the equations and all at the same time.
I was just sharing my thoughts.
My logic tells me that if one likes two know any upcoming answer, it is usually to manipulate the outcome.
You just like what you do. I think. Like a hobby.
One which I like to read about.so
Go on... I was never here.
Is your coin rigged? Just kidding, those results aren't that unusual.
Originally posted by In nothing we trust
Here are my results:
10 flips
Results 6 Heads: 4 Tails
10 flips
Results 6 Heads: 4 Tails
He writes, “Here’s a true story, and I saw it happen. At Caesars Palace on July 14, 2000, at 1:35 p.m., the number 7 came up six times in a row at Roulette Wheel #211.
To figure the odds of such an occurrence, multiply 38 x 38 x 38 x 38 x 38 x 38, or over three billion to one!”
Black was said to have come up 23 times in a row at the Imperial Palace in Las Vegas (a dealer told me this in the early 1990s) or was that 22 times in a row at Caesars in Atlantic City (mid-1990s)?
Red once came up 21 times but I can’t remember who told me or where it was.
Originally posted by Arbitrageur
I don't understand the OP at all, I'm a statistics expert so maybe I'm too biased to be open minded about this. But to me the odds are 50/50.
And I suspect air pressure isn't a huge factor. When I flip a coin it seems to be spinning as fast when it lands as when it started, so if air resistance is slowing it down, which it probably is, it's not by much.
Originally posted by Arbitrageur
reply to post by Gentill Abdulla
right, if you used a machine to apply the initial force, you might be able to make it consistent enough to get a predictable result. When I use my thumb to apply the flicking force, it's not that consistent.
Originally posted by wl653
As noted above there are so many variables here that are not taken into account, this theory would only work in a vacuum because if there was any form of crosswind or temperature difference the results would be thrown off.
Or consider, is the room a 0 degrees kelvin or somewhere around 1235 degrees kelvin(the melting point of pure silver, assuming the coin is silver)? This matters because not only will the surface area of the coin be smaller at absolute zero than it will at 1 degree below its melting point, if we're in extreme temperatures the metal becomes easily malleable. Although the odds of either of these extremes being tested it still holds true at more reasonable temperatures because of varying surface area.
Another odd case to consider: what if the coin is not circular but square, hexagonal or octagonal?
I'm not saying it is impossible to create a formula to predict the outcome of a coin toss but it would be a very detailed one that has to include every variable from temperature to imperfections in the specific coin.
Originally posted by YouCanCallMeKM
I have a book called " Numbers" In it there was a piece where it talked about Pascal and Fermat gambling on by flipping a coin. If the coin landed heads up Fermat won a point, tails up Pascal won a point. 1st to 10 points win. Both put down 50 francs, so the total would be 100 francs. They played the game until it was 8 points for Fermat and 7 points for Pascal.(Also keep in mind that they did this threw sending letters of there results to each other back and forth) They had to stop playing tho because Fermat received a message that a friend was very ill and he had to leave immediately. Here is a part from the book on how they decided to split the pot.
Dear Blaise.
As to the problem of how to divide the 100 francs, I think I have found a solution that you will find fair. Seeing as I needed only 2 points to win the game, and you needed 3,I think we can establish that after four more tosses of the coin, the game would have been over. For, in those four tosses, if you did not get the necessary 3 points for your victory, this would imply that I had in fact gained the necessary 2 points for my victory. In a similar manner, if I had not achieved the necessary 2 points for my victory, this would imply that you had in fact achieved at least 3 points and had therefore won the game. Thus, I believe the following list of possible ending to the game is exhaustive. I have denoted "heads" by an "h" and tails by a "t". I have starred the outcomes that indicate a win for myself.
hhhh* hhht* hhth* hhtt*
hthh* htht* htth* httt
thhh* thht* thth* thtt
tthh* ttht ttth tttt
I think you will agree that all of these outcomes are equally likely. Thus I believe that we should divide the stakes by the ration 11:5 in my favor, that is, I should receive (11/16)*100=68.75 francs, while you should receive 31.25 francs
I hope all is well in Paris. Your friend and colleague
Pierre
Originally posted by nh_ee
reply to post by Gentill Abdulla
With any equation, you are only able to solve for one variable at a time.
You have too many variables in your hypothetical equation to solve for a valid solution.
For starters.
Some of the variables you have defined could better be considered as constants.
Air Pressure or Barometric Pressure would be negligible in a trajectory of 10 feet or less and would be considered a constant as far as your equation is concerned.
If it did influence the coin's trajectory, it would be minuscule at best.
One would need to change altitude considerably before air density enters into the equation and would effect the trajectory of a simple coin toss.
Because there are two sides to the coin, due to it's highly improbable for it to land on edge IMA, it is called a binomial equation which translates to Heads or Tails.
And subsequently ends up averaging out to resulting in around 50/50.
Take a course or two in Physics and Calculus.
It will reveal quite a bit about how statistical models actually work.
Originally posted by ikonspyre
absurd exercise of brain power.....better spent figuring out real solutions to real problems.
Originally posted by Gentill Abdulla
Originally posted by ikonspyre
absurd exercise of brain power.....better spent figuring out real solutions to real problems.
I would like to think that I help find solutions for some problems in the world.
The system involves card counting and the team is split into two groups. "Spotters" play the minimum bet and keep track of the count. They send secret signals to the "big players," who place large bets whenever the count at a table is favorable.
the first highly capitalized "bank" of the MIT Blackjack Team started on August 1, 1980. The investment stake was $89,000, with both outside investors and players putting up the capital. Ten players, including Kaplan and Massar, played on this bank. Ten weeks later they more than doubled the original stake. Profits per hour played at the tables were $162.50, statistically equivalent to the projected rate of $170/hour detailed in the investor offering prospectus. Per the terms of the investment offering, players and investors split the profits with players paid in proportion to their playing hours and computer simulated win rates. Over the ten week period of this first bank, players, mostly undergraduates, earned an average of over $80/hour while investors achieved an annualized return in excess of 250 percent.