posted on Dec, 21 2018 @ 12:45 AM
So, there is 1 VDC going across a 10k ohm rated resistor into the negative leg of the amplifier. The amplifier also has a positive and negative 50 VDC
going into it. For the life of me I can't remember how the diode, 100k ohm resistor, and normally closed contact play into the equation. I took a
break from it and watched a movie, but coming back to it I still can't get it. I've forgotten some fundamental.
Ohm's law is V=I*R. So, 1 VDC= (?)I x 10K ohm. So, I=.0001
One can get Power(P) by:
V*I, I squared x R, or V squared / R
I just multiplied the voltage by the amperage and got .0001 for the power.
Therefore, I've got .0001 amperage(power) and voltage going into the amplifier.
You know I think I just mixed up some calculations when I got 10 VDC. I'm fairly certain that it's -10 VDC.
edit on 21-12-2018 by
RealityIsAbsurd because: (no reason given)