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1] Dioxygen difluoride reacts vigorously with nearly every chemical it encounters – even ordinary ice – leading to its onomatopoeic nickname "FOOF" (a play on its chemical structure and its explosive tendenciesText
Again, there's a lot of energy tied up in the molecular bonds of this chemical, and the lower the energy required to form a bond, the more stable the molecule. Therefore, even at extremely cold temperatures (-160*C) in complete isolation, dioxygen difluoride decomposes to oxygen difluoride (OF2) and O2 gas. At room temperature, this decomposition is uncontrollable (no-one's gotten it anywhere close to RT without it coming apart), and even at extremely cold temperatures, the heat produced by slow decomposition can cause what's called a "thermal runaway"; the heat produced by one molecule decomposing is absorbed by nearby molecules causing them to decompose, releasing more heat, and so on. When things rapidly decompose into more stable gaseous components, the event is normally accompanied by a loud noise and shrapnel, formed from the remains of whatever had been holding the substance and anything else nearby.
Of the products formed by the self-decomposition of FOOF, oxygen gas is a pretty strong oxidizer, but it's the least of our worries here. The other product, oxygen difluoride, is almost as strong an oxidizer as dioxygen difluoride, which is only stronger because it's oxygen difluoride plus more oxygen. The "shared" electron pairs forming the bonds between the oxygen and each fluorine atom are much more closely attracted to the fluorine, as opposed to a structure like water where the oxygen is the more attractive. This gives the oxygen a formally positive oxidation state of +2. By its very nature, oxygen yearns to flip that sign and achieve its "natural" -2 ox state by bonding with something less electronegative (which, as previously mentioned, is almost everything else in the periodic table besides fluorine). However, unlike the other oxygen atom in the FOOF molecule which flew the coop, this second oxygen can't escape, because the two fluorine atoms won't let it go. The fluorines prefer to bond to it rather than to each other... until something else, anything else, is introduced that's even more attractive.
pitiful self-bump here*
A reply to all of you, because I didn't know exactly what I was asking. Where I was going with the topic is that I have so many questions about how easily it could be distributed (as chemtrails, I suppose) to cause the most damaging effects (it would literally rain fire).
No. Gold and fluorine do not "attract." But when gold is heated (red hot), and exposed to fluorine it will produce gold fluoride.
The jist of what I'm reading is that gold and fluorine attract and when water is introduced to that mix it is highly explosive.
Gold pentafluoride is the strongest known fluoride ion acceptor, exceeding the acceptor tendency of even antimony pentafluoride.
Gold(V) fluoride can be synthesized by heating gold metal in an atmosphere of oxygen and fluorine to 370 °C at 8 atmospheres to form dioxygenyl hexafluoroaurate
Releasing elemental fluorine? Ok, sure.
I'm merely saying that aside from nuclear bombs (that ruin the land and atmosphere for eons) the application of this quicker, cleaner method would make more sense to some.
No idea what gold has to do with it though, since as pointed out, it will only combine with fluorine at high pressure and temperature.
No. I don't. Are you talking about atmospheric high pressure systems? They do not produce 8 atmospheres. Especially at the altitudes at which jet planes fly.
I think you understand what I am getting at.
No. HAARP could heat ions in the inosphere by a couple of hundred degrees. It had no effect on neutral particles in the the atmosphere.
No. Napalm does a pretty good job of that though.
Would these elements/molecules then 'stick' to drop as rain of fire singing everything (even cement and metal) in it's way?
Fluorine itself, the chemical element, is the most reactive of substances; and does not occur in nature. It combines rapidly and violently with whatever it touches except its own compounds. Prior to 1942, it was made with great difficulty, in gram quantities; and could not be bought at any price. The problem of containing it was solved by treating materials to form a tight surface coating of fluoride. This protects the underlying material from further attack. It is now shipped in tank-trucks of 5,000 lb capacity. The consequences of a wreck were not pleasant to contemplate. There would be no explosion, but it would consume everything it touched, including water, steel, concrete, and people. The heat would be terrific. The products of combustion would all be poisonous, and most of them corrosive; enough poison to kill a million people would result; and decontamination would be a major undertaking. Fluorine is also being tried as a rocket propellant. With hydrogen or hydrazine as fuel, it makes the most effective chemical propellant that is possible. We are told (37) that it creates no toxic hazard, but this is hard to believe.
originally posted by: dianashay
a reply to: Phage
Napalm would leave fatal residue would it not?
It also deoxygenates the air, and releases too much carbon monoxide? It is a dirty bomb.
The combination of chemicals I refer to cause a melting into sludge, or slurry. All evidence of it being there is eventually burned through the ground until it is neutralized (burned out).
I get what you are saying though, there would be damage to everything in it's acidic path, there would be far cleaner methods, especially if just randomly tossed over everything. It would melt everything and anything in such a large area.