You provided your own answers in your first, third and lady photos.
That's the short version, sigh...but,
That's not going to help me, to get you off my back, since you clearly will not see that simple answer, already from the first time on, that you
posted all that crap, without providing any links btw. And totally not understanding your own crappy posting material.
But I understand now that you have no clue at all, so I have to explain it to you,
or you will keep littering this and other threads, with your obvious misconceptions.
And, believe me, I try to educate you, not to humiliate you, it's sometimes a tad bit hard, I have to admit that, to be honest, (smile) :
Your Photo 1, 2 and 3.
LT : Big angle of camera to 747, in your Photo 1, so, appears much smaller than in your Photo 3.
And flies AWAY from the camera, and is or filmed further away from it, than in your Photo 3, or is zoomed in, in your Photo 3, thus that 747 length
shows even more shrunken.
RULE nr 1 : You can only compare data from the exact same situation. (Use a ruler) .
As can be done indeed in the Pentagon situation, because those 2 cameras were stationary.
With only ~ 4 m distance from each other, but per individual camera its 27 frames per second, comes then from the exact same situation per camera.
Camera data can then thus, frame by frame, from the same camera, be compared.
Camera angle following that 747 in your photos seem to be ~ 45 degrees, so, if that 747 would be portrait as in the same situation as the recorded
9/11 plane, AA77, namely according to you, come flying TOWARDS the camera under an angle of ~ 45 degree to that camera, it would have appeared 30 %
shorter. And should now too, but it doesn't. (Use ruler) .
It flies away from the camera, and, much more important, at a different distance from the camera, or, more likely, is zoomed in, what I suspect. Pay
also attention to the black tripods in your Photo 1 and 2. These are absent in your Photo 3. Thus,
your Photo 3 is zoomed in.
And also watch the ~ 20 degrees angle of the darker green band of grass in the bottom parts of your Photo 1 and 2, while that same band in your Photo
3 is lined perfectly parallel to the photo bottom. Thus, exactly comparable now, with the 2 Pentagon camera positions.
And as you can compare your Photo 1 and 2 now with your Photo 3, which Photo 3 does show a comparable situation as on 9/11, namely a 747 perpendicular
to the camera lens, thus showing the full known length of that 747, you'll find that your 747 in Photo 1 is not 30 % smaller, but more than 50%
smaller than in your Photo 3. (Use ruler) .
But since the camera was zoomed-in in Photo 3, and thus showed a longer full length than if the camera-man would not have zoomed-in, that's why you
measure there in your Photo 1 and 2, a 20 % less 747 length than in an equal zoom situation. Thus thinking it is > 50 % smaller, instead of 30 %
smaller than the photo in your Photo 3, which would comply to an in a same situation used camera, and Mathematics shows you, that it then always
becomes 30 % smaller in a photo. See my explanation for that in one of these pages.
And always 30 %, but only if you can keep your fingers off the lot of camera settings, and fix the camera on a stable sturdy tripod, where again the
fingers-off rule applies. Only then, applies the 30 %. Just as for the Pentagon cameras, and AA77 applied.
The 4 lady photos.
I hope for you that you will understand that the one posting that lady photo (btw, link.? ) does not explain positions as I do. They use the first
photo (1) as straight on, but should describe it also as 0 degrees, since they call the fourth photo (4) as 90 degrees.
While I say that the plane shows its left side perpendicular to the camera lens position, thus under an angle of 90 degrees.
I would describe your small lady photo (4) as taken under an angle of 180 or 0 degrees, since the camera is stationary.
EXAMPLE : Lay a full, or half circle protractor, flat on the table in front of you, with the 90 degrees sign perpendicular to but away from your body.
Lay your stretched right hand parallel to the black line on it, that is drawn between both 0+180 positions, against that 90 degree position, so with
your stretched right hand, parallel to that black line and also to your body, and that's the situation in photo (1), and then move that open hand
along the protractor to the right 0+180 position, that's photo (4). In between are positions of photo (2) and (3), nearing 0 degrees, and these seem
more and more smaller to the camera, in this case, your eyes, in this example.
I do hope now that you at last understand that the greater the angle to the camera becomes, thus near 90 degrees, the more the plane (or lady) reaches
real life dimensions.
The smaller the angles toward the camera, towards 0 degrees, the smaller the plane (or lady) will appear.
files.abovetopsecret.com...
[pic]ae63ad1bac.gif[/pic ]
You have been duped by the poster's different use of angles.
Did you read and see my post in pg 8 or 7 with the animated GIF in it, where there and only then, you can clearly see a long black shadow line under
the jet engine its trailing horizontal and very long and thick smoke column.?
.