The mathematics of hypothetical extraction of energy from the vacuum, page 6

reply to post by pause4thought

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Funneee
Best to ignore the C^2 part, and just see it as E=M.........

Originally posted by CLPrime
reply to post by Aletheia007

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So, are you using the observed 6×10⁻¹º J/m³ or the theoretical 10¹¹³ J/m³? 'Cause there's a big difference. Personally, I'd think the observed value would be preferred.

edit on 17-12-2011 by CLPrime because: (no reason given)

How can these numbers be so hughly different..? Somebody definitely screwed up or doesn't know what he/she is talking about....

Sec.line.

I know i keep haarping on about it, but here are some interesting books;

Modern Aether science

Physics without Einstein

Physics Unified

And for the algebra buffs;

String theory

The modern revolution in physics

Enjoy!

Here are some interesting articles;
The final theory
Bit of a slow link, be patient

reply to post by zatara

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The numbers are hugely different because we always talk about observable energy & mass in the universe, hence the 'dark matter/dark energy' theory.
The math says there is a big difference between observed energy/mass & calculated energy/mass.
If you really boil down quantum mechanics to, say, the higgs field, it's saying there is a point (call it Zero) where particles can appear & disappear.
If you really boil down Aether theory, it says the same.
If you really boil down string theory, it says the same.

The problem is that each of these theories have a different explanation for how this mass/energy exchange works. The real answer could also be all three at once, the universe is that crazy.

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