posted on Jan, 20 2003 @ 11:30 AM
Al Snyder pointed out another inconcruency in the Newtonian gravitation formula. He did this by comparing two sets of magnets, one set 10 times more
power than the first. Using the Newtonian formula, he showed that for the first set of magnets of power 1,
F = m * M / R^2
1 = 1 * 1 / 1^2
But for the second set of magnets 10 times more powerful than the first,
100 = 10 * 10 / 1^2
Newtonians would maintain that the second set of magnets are 100 times more powerful than the first set, instead of the actual 10 times more powerful
that we KNOW they are. Therefore, Snyder concluded that in the Newtonian gravitation formula, F is actually squared,
F^2 = m * M / R^2
For the second set of magnets 10 times more powerful,
10^2 = 10 * 10 / 1^2
F = 10
Could this mean that the force we attribute to gravity is exerted by a much less quantity of matter than previously thought to be the case? And could
this much less quantity of matter in a hollow earth exert the gravity force we observe the earth to have? Newtonians have presumed a much more massive
and dense earth than a hollow planet would seem to have.
However, even if we assume that the Newtonian mass and density for the earth are correct, this does not preclude the earth being hollow. It could
still be hollow even with a density of 5.5 gm/cc. Let's review how the mass and density of the earth are determined.
Newtonians assume, by Newton's Second Law, that the momentum of a small mass accelerating towards the earth near its surface is equal to the earth's
gravitational force acting on that small mass:
F = m * a
The Momentum Formula (Newton's Second Law)
F = GmM/R^2
The Newtonian Gravitation Formula
m * a = GmM/R^2
Solving for a, the mass m's cancel out,
a = GM/R^2
We can now solve for M, the mass of earth,
M = a * R^2 /G
using the Newtonian Gravitational Constant,
980.665 * 4.0678884 x 10^17 / 6.67259 x 10^-8 = 5.978541732 x 10^27 gms
The Newtonian mass of the Earth
From the Density formula
D = M/V
we obtain the Newtonian density of the earth.
From the volume of a sphere formula,
V = PiD^3/6
The volume of the earth is 1.082 * 10^27 cc.
The Newtonian density of the earth then is:
5.978541732 x 10^27 gms / 1.082 * 10^27 cc = 5.525 gm/cc
Since surface rocks have a density of 2.7 on average, the interior of the earth would have to be at least as dense as steel (about 8 times more dense
than water, water = 1) to arrive at the Newtonian average earth density of 5.5 (8.3 + 2.7 / 2 = 5.5).
Now let's ask ourselves some questions. For example, how dense would a hollow earth be? Would it necessarily be less massive than Newtonians claim?
How would gravity theory need to be revised to allow for a hollow planet? And if the gravitation formula and gravitation constant need to be revised,
what would they be?
These are questions that need answering if hollow planets are a reality. For an ongoing review of gravity and how it may affect the hollow earth, see
my study The Origin, Cause and Control of Gravity -- Found!
For now, let's visit the idea of whether an earth density of 5.525 gm/cc could be hollow.
Assuming the thickness of earth's shell at 800 mi or 1,287.48 km,
Diameter of Earth's hollow: Thickness of Earth's shell x 2 - Diameter of Earth
800 mi x 2 - 8000 = 6400 mi
Or
1,287.48 km x 2 - 12,756 = 10,181 km Or 1.018104445 x 10^9 cm
Volume of Hollow:
3.14159265 x (1.018104445 x10^9)^3/6 = 5.525551394 x 10^26 cc Volume of Earth - Volume of Hollow = Volume of Shell: 1.086781293 x 10^27 cc -
5.525551394 x 10^26 cc = 5.342261531 x 10^26
Density of Shell = Mass of Earth/Volume of Shell:
5.978541732 x 10^27 gms/5.342261531 x 10^26 cc = 11.19 gm/cc
This assumes that most of the earth's mass is located in its shell. As you can see, Newtonian physics would require an average shell density almost
as dense as lead (11.3). And since surface rocks are 2.7, then the interior of the shell would have to be greater than the average density.
The interior density using the Newtonian mass of the earth requires than the interior of the shell would have a density of 2 * 11.19 - 2.7 = 19.68,
which is denser than gold (19.3). Platinum is 21.4, so an inner shell density of 19.68 is not beyond the realm of possibility. In fact, if the earth
is hollow as we maintain, the inner shell would necessarily need to be of a greater density to give the hollow planet enough strength to keep its
hollow shape.
So we can say that a shell density of 11.19 gm/cc could be in the realm of possibility. After all, the earth DOES ring like a bell after a rather
large earthquake. A bell is hollow and is made of metal, just as a hollow earth may be.
We might ask how much of the earth's mass would be contained by the interior sun? Actually, an interior sun of the estimated diameter of 600 miles
would contain very little of the mass of the earth.
Assuming the interior sun has a density of glass which I claim all stars are actually crystals instead of burning gas, it's mass would be only .01%
of the mass of the Newtonian mass of the earth.
V = pi D^3 / 6
pi * (600 mi * 1.60934722 km * 100,000 cm) ^3 / 6 = 4.714130881 x 10^23 cc
Volume of inner sun
Let's assume that the inner sun is also hollow and has a shell 10% of it's diameter, or 60 miles. This would give the sun's hollow a volume of
2.413635011 x 10^23 cc. So the volume of it's shell would be 2.30049587 x 10^23 cc mutiplied by 2.6, the density of glass gives,
Mass = Volume * Density
= 5.981289262 x 10^23 gms, Mass of inner sun
divided by mass of earth of 5.978541732 x 10^27 gms
= .000100046 * 100 = .01%
If the interior sun is composed of gas as orthodox science maintains stars consist of, then that percentage would be much less. By far, most of a
hollow earth's mass would be located in its shell.
Another possibility, you may say, is that the earth's shell is thicker than 800 miles which would give it a lower average shell density. This also,
could be a possibility. Some method of determining the shell's thickness needs to be devised. This could easily be determined by entering the hollow
of the earth through a polar opening and bouncing radar waves off the opposite side of the hollow interior.
In all, actually, I see nothing in the Newtonian mass and density of the earth that would completely exclude the earth from being hollow. Earthquake
waves have been noticed to bend as they descend into the earth causing them to curve back up to the surface before hitting the discontinuity inside
the earth that scientists claim is the outer core. This indicates the earth does increase in density with depth which is consistent with a hollow
shell using the Newtonian mass of the earth. In fact, if the earth is hollow and the Newtonian mass of the earth requiring an increased density with
depth is correct, then that in itself would exclude their claim to a molten interior. That discontinuity inside the earth could be the inner surface