posted on Feb, 17 2005 @ 09:33 PM
This is an idea for a reactionless engine that can be built with pistons and cylinders:
imagine you are at the top of a 10 story building, at the bottom a cannonball is shot horizontally and is tight with a rope you are holding with a
frictionless gloves
lets neglect gravity and consider the rope weightless, the ball is going straight and since you are letting the rope glide in your hands it keeps that
direction for as long as necessary
you apply a force or tension to the rope of 1 kg during one second when you are right above the cannon, that pulls you downwards but the trajectory of
the ball is now slightly upwards
you wait for as long as necessary without applying tension to the rope
till the ball is in your horizontal
now when the cannonball is in your horizontal you keep a constant tension of 1kg on the rope what means you are being pulled rightwards and UPWARDS
at a given moment youll have the ball going totally upwards so all you have to do is hold the rope tight and be pulled up
when the ball is shot you apply the 1 kg tension when the ball is right underneath you
if after applying the 1 kg tension the ball takes 1000 seconds to get to my horizontal it would be the same effect if I applied a constant tension of
1 gram during those 1000 seconds this would be more convenient
by holding a tension of 1 gram or 1 kg I mean to let the rope glide and go away in such a way that the force indicated by a dynamometer put in the
rope would be that one of 1 gram or kg actually my gloves wouldn’t be frictionless anymore they would cause a slight friction that would cause a
slight tension
there will be a transformation of the kinetic energy into a very slight down and lateral thrust first and then a bigger up and lateral thrust the
lateral thrust is annulated by a symmetrical set that acts like in a mirror
lets suppose we throw the ball with a given energy and we apply a tension of 1 gram during 1000 seconds, the radius will increase a lot and the w
decrease a lot so if it took to the ball to reach my horizontal 1000 seconds in reaching my vertical might take 2 or 3 or even 10 times more depending
on the tension, the less the tension the more the radius what means the less the w and the more time the 1 gram force is applied in each quarter
so the initial kinetic energy is transformed into horizontal force and vertical force of which the upwards force will be 2, 3 or 10 times more than
the downward force depending in the applied tension in the rope or the resultant radius
one of the interesting things of my engine is that like it is kept all time spinning the lateral forces are kept as energy
to build this engine would be very simple you need a pair of hollow cylinders that spin holded by their middle counterotatory in the inside there are
two pistons facing each other and that always keep a constant distance so when one expands the other retracts
the movement is made in such a way that while the cylinder spins the piston that is pointing to 6 oclock is let go away from the center of spin and
therefore the piston aiming to 12 is taken towards the center, when the pistons reach the horizontal the senses are inverted and the piston that
before was let away from the center now is taken towards the center, each piston will be at the same distance from the center when they are vertical,
when they are horizontal the difference in distance of each piston to the center is maximum one piston will have move totally away from the center
while the other piston will have even pass through the center
said with another words all times a piston is in the bottom half of the circle its let go away from the center and if its at the top of the half is
taken towards the center
the more the variation of radius the more the thrust therefore would be interesting that when the piston is taken towards the center it can go through
it and pass it
like the w tends to keep constant since one piston tendes to acelerate the w and the other to decelerate it appears also a lateral thrust because the
centripetal force is bigger in one half than another so taking into account that there are two forces acting separated 90 degrees is the resultant of
this two forces the one to be used in this way if we want to go towards 12 oclock the cycle would start (when the pistons are balanced) at 4:30 one
cylinder and at 7:30 the cylinder that is spinning the opposite way taking into account that the imaginary line that unites both cylinders axes go
from 9 to 3 oclock
I have found the easiest way to calculate the direction of thrust by calculating the tension that each piston applies in the axe of the spinning
cylinder
theres only one gearing necessary and would be the one that relates the spinning with the movement of the pistons to this same gearing could be
attached the spinning force that would produce the thrust I think the ideal would be using a motorcycle chain to unite the ends of the cylinder where
the axes of the pistons are with the center axe of the cylinder using two chains for each piston axe united to the cylinder axe for reasons of
balance
the amount of thrust depends on the w, the variation of radius and the weight of the pistons
i believe the reason for this device to work is that the centripetal force ( the tension) is much higher in the inwards spiral (second quarter) than
in the outwards spiral (first quarter) even though they are simetrical
I also have an idea to test gyroscopic inertial thrusters by holding the thruster in a cable that instead of being attached directly to the ceiling is
attached to a cart with wheels that goes on rails being these rails on the ceiling