Need help with a problem cant figure out.

My brother has been stuck on this problem for the last 30 minutes and is getting frustrated. I tried to go at it but couldn't figure it out either. can someone please help him out with this problem for his homework.

Its #3ibb.co...
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a reply to: ElOmen
o_0
If this is the worst problem you have in Texas, count yourself lucky man!

a reply to: ElOmen

How do you get more than 12 ounces in a 12ounce can?

Basically. Take your minimum value and your maximum value. Subtract the max from the min, and that's your range. Divide that range by the number of classes you have. That's the step between each class. Start from the min and add the step to it. That's your first range, continue until you've done all 7 classes. Then mark the the number of times a number appears in that range.

a reply to: Aazadan

Thanks appreciate the answer. He gets all that he just gets confused with the decimals and rounding off part.

This is the kind of click bait nonsense that makes me want to ban ATS from my life.
right along with buzzfeed and wikihow, and google services.

quit ruining the internet and go back to sungazing.

a reply to: lordcomac

What are you talking about?

a reply to: myselfaswell

The same way you get more than 100%???

a reply to: Aazadan

You said what???

originally posted by: myselfaswell
a reply to: ElOmen

How do you get more than 12 ounces in a 12ounce can?

Measure by volume...freeze the contents first.
Do I win anything?

originally posted by: myselfaswell
a reply to: ElOmen

How do you get more than 12 ounces in a 12ounce can?

stack the same number of Troy Ounce coins in the same 12 ounce can, then secure the lid...


using the principle....
1 kilo = 35.27 Oz
1 kilo = 32.15 Troy Ounces

originally posted by: Sillyolme
a reply to: Aazadan

You said what???

Basically, in a histogram you need to divide the groups of numbers up into ranges, then you're recording how often a value in that range appears. So to get equal ranges you take the maximum value minus the minimum value and divide by the number of values you want. That's the size of each range. Starting at the minimum you add that size to it, to get the top value of each number in the range. Once you have that done, it's simply a matter of going through and marking them correctly.

The whole process gets easier and is less error prone if you sort the list first

originally posted by: ElOmen
a reply to: Aazadan

Thanks appreciate the answer. He gets all that he just gets confused with the decimals and rounding off part.

You don't actually want to round off here. Because the values you're given go out to two decimal places, but your steps go out to three, it means you're never going to wind up in a situation where a number is right on the edge of two of the steps.

I didn't explain it last night but if your ranges are 1-2, 2-3, 3-4, 4-5, then if you're given the number 3 it can technically fall into either category. So you would actually want those ranges to be 1-1.99999, 2-2.99999, 3-3.99999, and so on. Depending on how strict the math teacher is, you might need to do that here, but the lesson as set up avoids the problem by making the decimal points for the steps expand past the data given.

*ahem*
friendly reminder you are asking this in an conspiracy forum

a reply to: Aazadan

Oh now your just being mean. I'm right brained. Numbers may as well be Sanscrit.

No matter what the problem regarding your homework is, you need not fret. There are so many online websites that will help you finish your assignments. You can either hire services to do it or you can learn from tutorials.

originally posted by: penmypaper
You can either hire services to do it

That's likely cheating, and defeats the purpose of gaining knowledge for yourself.

or you can learn from tutorials.

Depending on the assignment rules this can still be cheating.