a reply to: KrzYma
As I recall, i gave you a lengthy description of how one such detector worked... you brushed it off and said something along the lines of "You don't
know how it works, its all just EM waves" without actually being coherent in your reasoning why.
Single photon counting is a well established and understood process. You have previously claimed light propagates from a source and previously have
stated that light sources propagate in a spherical wave front. We pointed out soon after that lasers don't behave at all like you described. You never
got back to me on that one either.
Let me give you an example. In my current work, we are characterizing the performance of single photon counting devices at deep uv wavelengths, around
170-190 nm now, this is the wavelength. We use a broad band flashlamp that produces light from around 160 to 1000nm (Xenon flash lamp) Due to the
atomic structure of Xenon, the emission spectrum has lots of peaks in it, and a long underlying continuum caused by the rather large amount of energy
levels and electrons the Xenon atom has.
So, we are only interested in the 180nm region so we use narrow band filters. These filters are made from tuned layers of different refractive index
materials, typically in a 1/4 - 3/4 layer structure, where one layer is 1/4 wavelength thick, and the next ontop is 3/4 nm thick, and so on, and so
on. So wavelength does appear to be a real thing. It is both a reflection of energy, but also takes some geometrical form too.
The flash lamp produces many many photons, the optical power is around 5 Watts at maximum pulse frequency (whole spectrum) We filter this using
optical components as described above and we focus the light onto a device. By applying 4 filters, collimation, focusing and mirrors we can reduce
this signal down to single photon level.
The device we are testing is a pixilated geiger mode APD, and contains a shallow junction. Why? well because photon absorption by silicon is very high
in the UV, meaning that technically UV gets very readily absorbed, and you will only see a signal from the device if the photon penetrates deep enough
to generate charge carriers (electrons - Holes) near to the junction such that they trigger an avalanche process in the device.
The device has some interesting features. The sensitivity of the device is directly related to the wavelength of the light imparted on it. And the
signal intensity is related to the amount of photons. The way you describe things, your explanation for these effects is simply that the only property
here is that of waveform intensity, and that its all about electrons not being 'at the right place?' You realize how illogical that is? How many
electrons do you think there are? I can tell you that, it is quite a lot.
By your own reasoning you seem to suggest that, if it is a geometry affect 'being in the right place' depending on the waveform, we could test this by
using a polarized laser, this allows us to control the polarization of the waveform and the wavelength very precisely. And let me tell you that...
single photon counting in a device as discussed above, behaves in a Poissonian manner, meaning the signal being generated is due to a discrete
quantized source. This behaviour does not change using a polarized laser source.
So if you take planck equation and do a similar calculation as you have seen in above posts, you can, given a light source wattage, calculate the
number of photons for a given wavelength. You can apply neutral density filters to reduce the amount of light at all wavelengths by equal amounts. SO
if you take a source that is producing of light at a single wavelength and apply lets say neutral density filters that give you a factor of 10000x
reduction in signal, resulting in what theoretically should be 10 photons emerging (on average) from the filter, you measure this using a device with
independently calibrated and it says, "I see a signal equivalent to 10 photons" the wavelength of your source is 500nm.
Now, you switch the source for a different one... this time it is at 200nm, you apply the same 10000x reduction and your detector has calibrated
efficiency meaning its efficiency is equal at 200nm as 500nm. So what is your signal? By your own logic you state that single photons are not a thing,
so you expect your signal to look the same regardless of wavelength. What you actually see is your detector telling you that you see 4 photons.
Well because E = hc/lambda, at 500nm the photon has a theoretical energy of 2.47eV, so your 10 photon signal is 24.7 eV worth of energy. Now the other
light source, at 200nm each photon is about 6.2eV but the source power is the same right? well the number of photons is actually not the same, despite
the power being the same.
The above experiment isn't fantasy, iv done it, you can do it too, (though you'd need equipment that is expensive and not really worth buying to just
do that experiment) and i can confirm the above behavour... and not what you seem to suggest which is that 1) single photon counting isnt a thing and
2) wavelength/wattage relations are also not a thing.