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No. The Earth's shadow is significantly larger than the Moon. In particular, since this was a "super Moon", when the Moon is closest to the Earth.
Rather, the Earth's shadow is a perfect circle that
casts a shadow sized exactly overlaying the moon's circular totality.
The "bulge" is too small to be noticeable. An exaggerated diagram:
SO where is the bulge and imperfections in the shadow?
originally posted by: Kandinsky
a reply to: imd12c4funn
He doesn't literally mean 'pear-shaped,' he means slightly short of spherical.
there is no "slightly short of spherical" to the shadow.
originally posted by: Kandinsky
a reply to: imd12c4funn
He doesn't literally mean 'pear-shaped,' he means slightly short of spherical.
originally posted by: Xtrozero
originally posted by: Kandinsky
a reply to: imd12c4funn
He doesn't literally mean 'pear-shaped,' he means slightly short of spherical.
Can we rule out flat...hehe
originally posted by: Xtrozero
originally posted by: Kandinsky
a reply to: imd12c4funn
He doesn't literally mean 'pear-shaped,' he means slightly short of spherical.
Can we rule out flat...hehe
No. It wouldn't.
Mt. Everest measured from the center of Earth which would be noticable with an overlay
originally posted by: Phage
a reply to: imd12c4funn
there is no "slightly short of spherical" to the shadow.
Again, the difference is too slight to be visible.
Yes. Like I said, a difference of 0.3%.
a difference of 25.41 miles.
It's not as minute of a difference as you make it sound.
originally posted by: imd12c4funn
a reply to: muse7
But as the shadow moves across the moon until total eclipse is achieved and then moving onward until the shadow no longer casts on the moon, you can see the arch of the shadow and that is where you can see there is no bulge or pear shape to the shadow. It is a perfectly circular arch.