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Arbitrageur
f you're talking about relativistic contraction in the direction of linear motion, isn't that dependent on the observer's frame of reference? In other words, an observer on or in the spinning disk wouldn't see the contraction due to linear motion that an external observer would observe.
Bedlam
Arbitrageur
f you're talking about relativistic contraction in the direction of linear motion, isn't that dependent on the observer's frame of reference? In other words, an observer on or in the spinning disk wouldn't see the contraction due to linear motion that an external observer would observe.
If it's a rotating sphere, what is an observer's viewpoint on the thing? There's such a gradient of temporal distortion, relativistic contraction and whatnot that you'd likely be hard put to find a consistent internal frame of reference. Unless the diameter was very large.
ImaFungi mentioned a galaxy in the original question which is more of a disk so I'll use that as it's easier to address a disk than a sphere. Mount some laser rangefinders located at the disk axis pointed in various directions to the disk edge. Since they are moving along with the disk, they will not see a contraction of the disk in one direction due to linear movement that an outside observer would observe. The laser rangefinders should observe radial symmetry, shouldn't they?
Bedlam
If it's a rotating sphere, what is an observer's viewpoint on the thing? There's such a gradient of temporal distortion, relativistic contraction and whatnot that you'd likely be hard put to find a consistent internal frame of reference. Unless the diameter was very large.
Arbitrageur
The laser rangefinders should observe radial symmetry, shouldn't they?
Arbitrageur
reply to post by Bedlam
Are you talking about radially symmetrical contraction?
The reason I ask is because you were talking about the disk rigidity and I didn't really get where you were going with that.
Bedlam
reply to post by ImaFungi
More, for a comparatively small sphere with a boundary rotational velocity approaching C, you have a huge gradient of relativistic behaviors varying from profound at the outer edge to zero at the axis.
ImaFungi
Bedlam
reply to post by ImaFungi
More, for a comparatively small sphere with a boundary rotational velocity approaching C, you have a huge gradient of relativistic behaviors varying from profound at the outer edge to zero at the axis.
And that zero at the axis is why black holes are 'infinitely dense'?
Kashai
reply to post by Bedlam
The fictional sphere occupies space and time in fiction and as does a black hole in reality.
Kashai
Any thoughts?
Kashai
reply to post by Bedlam
Rotating a mass near or at the speed of light should result in an implosion and for the record black holes are considered to have infinite density.
Any thought?