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Curiosity was set down on the Martian surface using a new high-accuracy entry, descent, and landing (EDL) system that was part of the MSL spacecraft descent stage. The novel EDL system placed Curiosity within a 20 by 7 km (12 by 4.3 mi) landing ellipse,[95] in contrast to the 150 by 20 km (93 by 12 mi) landing ellipse of the landing systems used by the Mars Exploration Rovers.[126]
Originally posted by Spacespider
reply to post by Watcher26
interesting theory
Please explain this video then...
Originally posted by BullwinkleKicksButt
I think you have made a mistake.
It is the cross-sectional area not the diameter that is relevant.
51 feet diameter parachute has a cross sectional area of 2042.8 square feet
2042.8/100 = 20.43 square feet which then converts to a diameter of 5.1 feet.
Then if you multiply 20.43 square feet x 3 = 61.29 square feet which then converts to 8.8 feet diameter equivalent on earthedit on 17-7-2013 by BullwinkleKicksButt because: (no reason given)
Originally posted by Watcher26
Originally posted by BullwinkleKicksButt
I think you have made a mistake.
It is the cross-sectional area not the diameter that is relevant.
51 feet diameter parachute has a cross sectional area of 2042.8 square feet
2042.8/100 = 20.43 square feet which then converts to a diameter of 5.1 feet.
Then if you multiply 20.43 square feet x 3 = 61.29 square feet which then converts to 8.8 feet diameter equivalent on earthedit on 17-7-2013 by BullwinkleKicksButt because: (no reason given)
Good point. I've never been great at math. But nevertheless the two ton (on Earth) Curiosity rover would have dropped like a stone.
Originally posted by Watcher26
Originally posted by BullwinkleKicksButt
I think you have made a mistake.
It is the cross-sectional area not the diameter that is relevant.
51 feet diameter parachute has a cross sectional area of 2042.8 square feet
2042.8/100 = 20.43 square feet which then converts to a diameter of 5.1 feet.
Then if you multiply 20.43 square feet x 3 = 61.29 square feet which then converts to 8.8 feet diameter equivalent on earthedit on 17-7-2013 by BullwinkleKicksButt because: (no reason given)
Good point. I've never been great at math. But nevertheless the two ton (on Earth) Curiosity rover would have dropped like a stone.
Originally posted by Spacespider
reply to post by Watcher26
interesting theory
Please explain this video then...
Yeah, but it didn't need to be "floating" down, either, considering that it had thrusters that would slow it down after the chute was cut from it. The chute was cut away 1 mile above the surface; Curiosity had no chute at all for the final one mile of descent.
Like I said in my post above, the parachute was designed to slow it down to 170 mph -- not slow it down all the way to a soft landing.
Originally posted by Biigs
Did you account for the fact that Mars has 62% less gravity than Earth?
Originally posted by Biigs
I thought the mars atmosphere was more in the region of 1% of earths, a tiny fraction of a percent doesn't sound right?
Not that im saying you are wrong but, where did you get your mars figures?