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Originally posted by trekwebmaster
If we do the "simple-math," it shows that: 0.99 - 0.0022 = 0.0078
edit on 2-11-2011 by trekwebmaster because: (no reason given)
Originally posted by trekwebmaster
reply to post by NoNameBrand
0.99 - 0.9878 = 0.0022
Originally posted by Illustronic
reply to post by trekwebmaster
The asteroid is going to be 150,000 km above earth and about 125,000 km above the moon at it's closest approach, plus the OP totally misunderstands the numbers he's adding together, explained by Alpha earlier in the thread.
Forget the x10 in this graphic, (it should be x100).
For better numbers use Horizons instead of the JPL applet, it even says so.
Originally posted by trekwebmaster
Originally posted by ngchunter
reply to post by trekwebmaster
Once again, our average distance from the sun is 1au, it is not a fixed distance, only an average. Our orbit is slightly elliptical.
True, but that's not what I'm questioning. Given that 1AU is approx. to 0.99 and an average, it's what is computed FROM that average. Are we in that LESS than 1AU away, or are we just a wee bit over the 1AU away from the Sun? One could miss by a country-mile and another could be a direct hit.
Originally posted by LightSource
On October 28th UX255 is .0111 AU from earth yet .4 LD from earth (or that is what is says on spaceweather.com).
On November 8th YU55 is .0079 AU from earth and .8 LD from earth how do those numbers add up?
Also UX255 was .0046 AU from earth on October 29th and YU55 will be .0022 on November 9th why didn't they use the other 2 numbers instead and when did .0111 become closer than .0079?
Originally posted by spikey
reply to post by ngchunter
I'm not saying anything jumped, i'm saying that the elliptical orbital path of the Earth is on a pretty gradual curve...never mind, it's not important.
What did your analysis show when you did the calculations with this other software you mention?
edit on 2/11/2011 by spikey because: typo