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So do you sit alone on the internet wondering that alot?
originally posted by: FlukeSkywalker
a reply to: MissSmartypants
I wonder what the energy is like in a 69 dimensional universe? I bet it's real NICE.
So in other words ....4D energy encompasses all the energy of all time all at once....and 3D energy is that amount of energy(4D) divided into little individual time packets. The snack size, if you will.
originally posted by: deckdel
a reply to: MissSmartypants
Valid point.
A 3D object has energy as a function of time: E(t). This is the time dependent sample of total energy.
A 4D object does not have time at all, thus just E.
That E is a sum of all time dependent energies at 3D world during its existence: E = Σ E(t), where t = 0 - ∞ (goes from 0 to infinity)
That total energy should correspond to the item’s mass, hence E = mc2. This is 4D total energy.
For time dependent 3D world, the only time dependent factor in that equation is the speed of light. Speed equals distance per unit of time.
E = Σ E(t) = Σ (m c(t)2) = Σ (m (300M/s)2) = Σ (m 90 Q (meters) / s2), where Q is for quadrillion, ie 1 with 15 zeroes after it.
m/s2 is measure of acceleration, where 1G equals 9,81 m/s2 and is the gravity on Earth. Lets make it 10 m/s2 for sake of simplicity.
Hence our equation becomes E = Σ (m 9 Q G), over 0 to ∞
This is a pretty big number of G’s we are talking about.
And would correspond to a black hole. At event horizon one experiences only 153 trillion G’s, so, our G number here is very very big.
Which means we do not really exist at all. And we are thus not having this conversation...
Wait. Wait.
I just realised one thing.
The only way you can project a 4D object to 3D world is to have the image of that 4D object in 3D world plus a black hole.
So the ”black hole” is a mathematical necessity to have a projection from 4D, but the projection itself is just an image on top of that black hole.
See my edit
originally posted by: deckdel
a reply to: MissSmartypants
Plus the black hole.
So, the image projection from 4D to 3D is rather imperfect. You get the image - plus a black hole.
The black hole contains all the energy needed by that image over the existence of that 3D universe.
originally posted by: deckdel
a reply to: MissSmartypants
Valid point.
A 3D object has energy as a function of time: E(t). This is the time dependent sample of total energy.
A 4D object does not have time at all, thus just E.
That E is a sum of all time dependent energies at 3D world during its existence: E = Σ E(t), where t = 0 - ∞ (goes from 0 to infinity)
That total energy should correspond to the item’s mass, hence E = mc2. This is 4D total energy.
For time dependent 3D world, the only time dependent factor in that equation is the speed of light. Speed equals distance per unit of time. For light that is 300 million meters per second,
E = Σ E(t) = Σ (m c(t)2) = Σ (m (300M/s)2) = Σ (m 90 Q (meters) / s2), where Q is for quadrillion, ie 1 with 15 zeroes after it.
m/s2 is measure of acceleration, where 1G equals 9,81 m/s2 and is the gravity on Earth. Lets make it 10 m/s2 for sake of simplicity.
Hence our equation becomes E = Σ (m 9 Q G), over 0 to ∞
This is a pretty big number of G’s we are talking about.
And would correspond to a black hole. At event horizon one experiences only 153 trillion G’s, so, our G number here is some 6 times bigger.
Which means we do not really exist at all. And we are thus not having this conversation...
Wait. Wait.
I just realised one thing.
The only way you can project a 4D object to 3D world is to have the image of that 4D object in 3D world plus a black hole.
So the ”black hole” is a mathematical necessity to have a projection from 4D, but the projection itself is just an image on top of that black hole.
And on down the chain dark energy shadows something else. It's turtles all the way down.
originally posted by: Ophiuchus 13
a reply to: MissSmartypants
Similar to how the observable universe shadows dark energy.
Thanks for the bump. You're a dear.
originally posted by: confound
originally posted by: deckdel
a reply to: MissSmartypants
Valid point.
A 3D object has energy as a function of time: E(t). This is the time dependent sample of total energy.
A 4D object does not have time at all, thus just E.
That E is a sum of all time dependent energies at 3D world during its existence: E = Σ E(t), where t = 0 - ∞ (goes from 0 to infinity)
That total energy should correspond to the item’s mass, hence E = mc2. This is 4D total energy.
For time dependent 3D world, the only time dependent factor in that equation is the speed of light. Speed equals distance per unit of time. For light that is 300 million meters per second,
E = Σ E(t) = Σ (m c(t)2) = Σ (m (300M/s)2) = Σ (m 90 Q (meters) / s2), where Q is for quadrillion, ie 1 with 15 zeroes after it.
m/s2 is measure of acceleration, where 1G equals 9,81 m/s2 and is the gravity on Earth. Lets make it 10 m/s2 for sake of simplicity.
Hence our equation becomes E = Σ (m 9 Q G), over 0 to ∞
This is a pretty big number of G’s we are talking about.
And would correspond to a black hole. At event horizon one experiences only 153 trillion G’s, so, our G number here is some 6 times bigger.
Which means we do not really exist at all. And we are thus not having this conversation...
Wait. Wait.
I just realised one thing.
The only way you can project a 4D object to 3D world is to have the image of that 4D object in 3D world plus a black hole.
So the ”black hole” is a mathematical necessity to have a projection from 4D, but the projection itself is just an image on top of that black hole.
Oh come on now be nice. Dont mess with them. You'll distract from the "awesome OP"...