posted on Dec, 3 2012 @ 01:28 AM
reply to post by Phage
Explanation: NO! Incorrect!
You left out Pi!
Therefor G = 0% of Pi ... NOT G = 0 .. because removing it from the equation simplifies the equation.
G its self has a measurable value [although only accurate to within the limits of our ability to measure that] and its value is G = 6.67*10E-11
Newtons of force.
Therefor, and since we are talking about ratio's [a/b] and percentages [%] there should be no issue setting one of the sides to zero % and defining
that as the flat 'rod'.
Personal Disclosure: The issue is not with the Big G of gravity ... its is the little g's of gravity [due to mass] at either end that are the n% of
Pi that bend the rod and it is here that my skill and talents in doing the maths break down.
Can you please help me resolve that?
How do I convert mass to little g .. and what amount of little g forces the 1 plancks length/second 'rod' to bend into a complete loop?
Would the little g's at either end have to add up to equal or more than the plancks mass of 2.176 51 x 10E-8 kg to force it into a closed loop?
Please walk me through the formula's ok.
Sorry if i come of as an uneducated tard with poor maths and geometry skills ok!
Even Einstein needed help with the maths and he was way smarter than I am ok.