posted on Oct, 22 2012 @ 02:30 PM
Originally posted by SplitInfinity
reply to post by Phage
Actually...you have just proved my point. You see...by describing Gravity as the source of Momentum and Energy...you made one FATAL FLAW in you
description which proves my statements.
You describe how the Pendulum swinging as being caused by Gravity...but in order for the Pendulum to be able to swing...a FORCE MUST FIRST LIFT THE
PENDULUM TO THE VERY END OF IT'S SWING OR THE FULL EXTENT OF DISTANCE BOTH HORIZONTAL AND VERTICAL FROM IT'S HANGING 6 O'CLOCK OR 180 DEGREE ANGLE OF
HANG WITH 0 OR 360 DEGREES BEING STRAIGHT UP PLUMB OR 12 O'CLOCK POSITION OF IT''S HANGING POINT WHICH IS PERPENDICULAR TO THE EARTHS SURFACE.
Without this lifting force whether it be a wench or a persons hand pulling or pushing the Pendulum's weighted end the distance both Horizontal and
Vertical as the distance to the Earth's Surface to the End Point of the Pendulum's Weighted Line or Wire or if you will...Steel Beam....will be closer
to the Earth's surface at the 180 Degree or 6 O'clock position as apposed to the Pendulum's weighted End Point being FURTHER AWAY FROM THE SURFACE OF
THE EARTH at the extent or end point or furthest point away from Perpendicular to the Earth at the END OF IT'S SWING.
This is proof that the Pendulum must be FORCED INTO MOTION. Gravity will not SPONTANEOUSLY move the Pendulum in a Perpendicular STATE OF REST...into
motion. The Pendulum must FIRST BE ACTED UPON BY A FORCE THAT WILL PULL OR PUSH THE PENDULUM'S END WEIGHT TO THE FURTHEST POINT OF IT'S SWING.
EVEN IN A VACUUM AND A THEORETICAL FRICTION LESS PENDULUM....THE RELEASE POINT OF IT'S BEGINNING DISTANCE WILL NEVER AGAIN BE ACHIEVED IN ANY SWING AS
GRAVITY WILL EFFECT IT AND THE VERY FIRST RELEASE WILL PASS PERPENDICULAR AND NOT ACHIEVE THE SAME DISTANCE OF HEIGHT OR HORIZONTAL DISTANCE. THIS
Phage is right.
It would be un-damped simple harmonic motion.
At the North Pole, where the 10kg mass is released, the force is all in potential energy and the initial velocity is zero.
Falling towards the center of mass, the object accelerates and the velocity increases. The potential energy is being converted into momentum.
Crossing the center point (the center of the Earth), its velocity is at its greatest, but it won't suddenly stop because the momentum of the object is
also at its greatest and will carry it on "upwards" towards the South Pole.
As the entire process is loss-less (frictionless), the object will continue to rise until velocity goes to 0 and the potential energy EXACTLY equals
what it was at the start. This is also exactly the same height that it was from the center of the Earth towards the North Pole, only this time, it is
towards the South Pole.
The whole process would be repeated going back the other way and since there are no losses in our imaginary scenario, the oscillation would continue
Of course in the real world, if such an experiment were technically or fiscally feasible, there would be frictional losses because we cannot make a
perfect vacuum. There are also likely to be magnetic frictional forces (Hysteresis) and while the start point of the 10kg mass was in orbit with the
Earth and would therefore track with the Earth's orbit, there would be issues of the mass hitting the sides of the tube (producing friction) due to
precession (Coriolis effect).
But Gravitation is not lossy and so the oscillation, in our perfectly frictionless imagined scenario, would be perpetual.
edit on 22/10/2012 by chr0naut because: (no reason given)