reply to post by swan001
Quantum Units Wild Guess
“In order to change an existing paradigm you do not struggle to try and change the problematic model. You create a new model and make the old one
obsolete.” ― Richard Buckminster Fuller
In my model, which is not likely to have anything to do with a change in paradigm, lol, the proton’s presence (three quarks if you like) is
literally composed of the high density spots that form at the overlap of the multiple quantum standing waves within the proton.
They are spherical waves that are bursting out of high density spots (HDSs), expanding spherically, overlapping, and forming new HDSs within the
proton. It is a continual process where the wave energy out flow that escapes the proton from the surface spherically (equal in all directions) is
replaced by wave energy arriving at the surface (directionally) from the out flow of wave energy from other particles. Thus the presence of the proton
is maintained by the inflowing and out flowing standing wave action.
Let’s say that we can freeze the quantum action process that has established the presence of a proton. That freeze frame will contain a finite
number of spherical quantum waves in overlap positions within the proton. Each overlap is a high density spot in my jargon. There are a finite number
of high density spots within the particle space where the spherical waves have overlapped at the moment of the freeze frame. That close configuration
of high density spots (lattice-like) has stability because there is no niche on the surface for any additional surface quanta or high density spots,
i.e. the surface wave energy out flow is equal to the wave energy inflow in a stable energy density environment, like at rest. (Increase the energy of
the environment and there are more surface quanta, hypothetically.)
The question is, from what we know about the proton at rest, and from what I speculate about the process of quantum action at the foundational level,
can we derive a ball park figure or even a wild guess of the number of high density spots (or shall we say quantum compression units) within a proton
In this exercise you might point out that the units of measure don’t work unless we define the whole exercise in terms of a new unit, i.e. a
speculative “quantum compression unit” that occupies an average amount of space per quanta in the freeze frame or lattice view inside a proton. We
are not talking about energy in joules for example because the units of measure wouldn’t work. Each quantum unit is a quantum of wave energy, not
only the individual spherical waves, but the high density spots that accumulate a full quantum and burst into new spherical waves. So the number of
quantum units would be the total number of spherical wave intersections that are present as hypothetically represented by the high density spots that
form and burst into quantum waves. Supposedly we could count the HDSs in a freeze frame of the proton, and if we could we would know the total energy
in quantum compression units of a proton at rest.
Wouldn't it be nice to have such a freeze frame and the ability to look inside the proton and see if it is composed of a vast number of quanta and
count the high density spots?
This hypothetical exercise is to put some perspective on the number of energy quanta in a proton and an electron at rest to quantify my idea of the
composition of a lattice of quantum units within a stable particle. For simplicity we will call these “average quantum compression units” which
simply occupy the space within the proton; a quantum unit would consist of one high density spot at the overlap of multiple spherical quantum waves.
This can also be thought of as the wave energy in quanta in a volume of space occupied by the proton accounted for unit by unit in a whole number. I
am proposing the following widely speculative guess at the number of these quantum units within the space occupied by a proton.
I am using the approximate ratio of the rest energy of an electron vs. a proton, which is 1/1836, to equate the number of quantum units in the proton
to the number of units in the electron and to give me some basis or connection to mainstream science.
In addition, I am supposing that the number of quantum units in an electron is equal to the number of quanta at the surface of the proton for various
reasons, but for this exercise that is just to have a relationship to allow us to do the calculations. That relationship is simply the result of
brainstorming with others the idea of doing this exercise in the past.
Area/Volume = (4 pi r^2)/(4/3 pi r^3) = 3/r = 1/1836,
therefore r=3*1836 = 5508, thus the radius of the proton is equal to 5508 quantum units.
4 pi r^2 = surface area of a sphere
4/3 pi r^3 = volume of a sphere
pi = 3.14159265
Quantum units in an electron = 381,239,356
Quantum units in a proton = 699,955,457,517
I'll just call it 400 million and 700 billion respectively, or even just hundreds of millions and hundreds of billions respectively :shrug:.