reply to post by TheMindWar
Let's try it with a more down-to-Earth analogy and mind exercise.
Picture a load of sand....give it any amount of mass that you choose. How about a round ton (tonne)...or, about 2,000 pounds
avoirdupois system of weights units.
The individual grains of sand will be representing the individual particles emitted by the Sun, in an X-flare burst.
A stone of mass....oh, let's say one hundred pounds is in free-fall (to mirror the asteroid on orbit). 2,000 pounds directly affecting the one
hundred pound mass will have a moment of inertia, and
could alter the path of the smaller mass,
if it is concentrated.....but,
that same quantity acting as individual particles (the "grains of sand") will not have the same localized moment of force upon the smaller mass, the
*rock* (or asteroid). The aggregate force is diminished, and diffuse.
With the idea of any re-distribution of Solar mass, in its entirety......due to the coronal ejection?
Logically, would seem that any mass that leaves the orb of the Sun......the total amount of ejecta, although by any Earth-bound measurement (on a
Human scale) might seem to be a huge value, will still be a tiny, tiny percentage of the Sun't over-all mass, and that which remains. Therefore, the
gravitational influence of the Sun, over-all, is essentially unchanged......any minor difference is so small as to be statistically insignificant.
edit on Thu 3 November 2011 by ProudBird because: (no reason given)