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Latest Picture of Comet Elenin, STEREO-B Will Capture First Today

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posted on Aug, 4 2011 @ 10:39 PM
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reply to post by Phage
 


I just looked at the new image gif available ,, in your opinion,, what is the NOW real time speed of the comet,, and has it changed,,, remember,,, its not 2sec,,, its 1.4,, and your right speed does make a difference,,

ohh for comparison:

Traveling at 50,400 kilometers per hour.,,,well can use that for a base point

time-period
of say ,,well whenever Elenin, first published his findings,,,

so 50,400 kilometers per hour,, times estimated distance,, =November

does not work if 50,400 kilometers per hour,, is no longer a valid piece of DATA/FACT,,

so my question,,
whats new speed estimate?
edit on 4-8-2011 by BobAthome because: (no reason given)




posted on Aug, 4 2011 @ 10:41 PM
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reply to post by BobAthome
 

The comet, like any object in an elliptical orbit (including Earth) travels faster the closer it is to its primary (the Sun). I don't know the current velocity of Elenin. I don't really care. It's now just inside Earth's orbit.

edit on 8/4/2011 by Phage because: (no reason given)



posted on Aug, 4 2011 @ 10:45 PM
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reply to post by Phage
 


"like any object in an elliptical orbit (including Earth) travels faster the closer it is to its primary (the Sun)."

ya its called small thing attracted to big thing,, you know there is a neat experiment involving a pos. charg and a neg. charge, and a bell jar,, but id probably bore you.

Sure wish some nasa guy could figure out how fast it was going,, i mean they hit a comet with a missle once,, so silly me , i guess they got lucky.



posted on Aug, 4 2011 @ 10:48 PM
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reply to post by BobAthome
 

Luck had nothing to do with it.



posted on Aug, 4 2011 @ 10:50 PM
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Originally posted by Phage
reply to post by BobAthome
 

Luck had nothing to do with it.


so my question,,
whats new speed estimate?



posted on Aug, 4 2011 @ 10:52 PM
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It would have to traveling faster than a Chevy Nova, right.

Thats pretty quick.



posted on Aug, 4 2011 @ 10:57 PM
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reply to post by guessing
 


chevy nova,,,har,,har,,#
how about a 55 chevy bellaire
#,,#,,



posted on Aug, 4 2011 @ 11:01 PM
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reply to post by BobAthome
 

Using the orbit diagram from JPL (what a good idea), its about 0.013 AU per day.
Call it 50,000 mph.

That wasn't so hard, was it?



posted on Aug, 4 2011 @ 11:07 PM
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reply to post by Phage
 


So then using

C/2010 (Elenin) is: 3.5 km = 2.17479 miles in diameter.
1 AU=93,000,000 miles

Traveling at 50,400 kilometers per hour.=November 8 2011
confirmed.

Excluding wobble.

ohhh "Call it 50,000 mph" would be a fail,,,its kilometers/hr


edit on 4-8-2011 by BobAthome because: (no reason given)



posted on Aug, 4 2011 @ 11:10 PM
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Originally posted by Phage
reply to post by BobAthome
 

Using the orbit diagram from JPL (what a good idea), its about 0.013 AU per day.
Call it 50,000 mph.

That wasn't so hard, was it?



actually ya it is,, u forgot too convert,,, boy that would have been a miss for sure,,,



posted on Aug, 4 2011 @ 11:13 PM
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reply to post by BobAthome
 

50,000 mph.
You have a hard time with numbers don't you.
0.013 AU = 1,208,426.54 miles



posted on Aug, 4 2011 @ 11:22 PM
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Originally posted by Phage
reply to post by BobAthome
 

50,000 mph.
You have a hard time with numbers don't you.
0.013 AU = 1,208,426.54 miles



0.013 AU per day. =0.013 AU = 1,208,426.54 miles


1,208,426.54 miles/ 12 hr day=100702.166666666666666666666667 miles / hr


100,702 miles per hour

thats about triple in speed from original 31,379.2452 miles / hr or 50,500 kph


actually i trouble with the convert miles too kilometers and all that euro crap.

and my original question

looks like new arrival date,, thats if someone can find a flaw in my math,,, which may be very likely,, so please ripp to pieces

thankyou
edit on 4-8-2011 by BobAthome because: (no reason given)



posted on Aug, 4 2011 @ 11:24 PM
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reply to post by BobAthome
 

Yeah. It's tough.
In Europe the days last 24 hours.



posted on Aug, 4 2011 @ 11:28 PM
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Originally posted by Phage
reply to post by BobAthome
 

Yeah. It's tough.
In Europe the days last 24 hours.

ya well like i said its only math,, u can divide or,, just start with the correct data like i was trying to point out,,, ohh the 24 hour thing,, ya thanks,, big laugh,,

fail



posted on Aug, 4 2011 @ 11:46 PM
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reply to post by Phage
 





cause if u use this chart .23 AU,,,

THE DATES don't match,,,,
Traveling at 50,400 kilometers per hour.
------------------------------
yup 3.5 km = 2.17479 miles in diameter. sounds about right
---------------------------------------------------
well mathematically anyway,,,,,,


Arrival Date:
November 8 2011

so the only variable would be SPEED
edit on 4-8-2011 by BobAthome because: (no reason given)


so my question,,
whats new speed estimate?
edit on 4-8-2011 by BobAthome because: (no reason given)



posted on Aug, 5 2011 @ 07:51 AM
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Originally posted by Phage
reply to post by BobAthome
 

Yeah. It's tough.
In Europe the days last 24 hours.

WOW, thank you SOOOO much for your incredible insight on this topic,
your input of information really brings clarity, thank you again for taking the time
tobring all this into perspective...



posted on Aug, 5 2011 @ 10:24 AM
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reply to post by Phage
 


Thank you amigo! I thought all the info I read on these pages is truth



posted on Aug, 5 2011 @ 10:37 AM
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Originally posted by Phage
reply to post by BobAthome
 

Yeah. It's tough.
In Europe the days last 24 hours.


RUN EUROPE, RUN FOR GOD'S SAKE!!!!

They're never gonna know what hit them... Have mercy on those poor souls, Phage, have mercy.






posted on Aug, 5 2011 @ 11:39 AM
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Originally posted by BobAthome
Arrival Date:
November 8 2011

so the only variable would be SPEED
edit on 4-8-2011 by BobAthome because: (no reason given)


so my question,,
whats new speed estimate?
edit on 4-8-2011 by BobAthome because: (no reason given)


Speed with respect to what?

Go to to the JPL Horizons system, and change the values to the following:



That will return results with respect to the sun. You can see that at 00:00 2011-Aug-05, the comet is 0.96483732888104 AU from the center of the sun (the "delta" value"). At 00:00 2011-Aug-06, the comet is 0.94732412073972 AU from the sun, meaning it traveled 0.01751320814132 AU in 24 hours. That works out to 109,164 km/hr average over those 24 hours.

Now lets look at it with respect to Earth. Change the ephemeris settings to the following:



Now we see that at 00:00 2011-Aug-05, the comet is 1.46063688418281 AU from the center of the Earth. At 00:00 2011-Aug-06, the comet is 1.44675238775646 AU from the Earth, meaning it traveled 0.01388449642635 AU in 24 hours. That works out to 86,545 km/hr average over those 24 hours.



posted on Aug, 5 2011 @ 03:00 PM
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Or one can just go to the JPL page and grab the Elenin orbital parameter page and turn on the
'Closest Approach Data' field. From there one can see that they quote a speed of 23.9 km/s
Since there are 3600 seconds in 1 hour that works out to be 86,040 km/s. A conversion to miles
per hour would be 53462.777 miles per hour OR 53462 mi's. and 1368.1 yd per hour.
website for converting km/s into mph.
www.metric-conversions.org...

Earth is said to be traveling around the sun at 67,000 mph.




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