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Originally posted by Tadeusz
Ah, the famous ÷ operator and 2 function.
As we all know p ÷ q is a binary operator which is equal to the log of q base p, and the function 2(x) is simply the factorial of x. Therefore
6 ÷ 2(1 + 2) = 6 ÷ 2(3) = 6 ÷ 6 = log_6(6) = 1.
Originally posted by Itop1
Once and for all i want to know the real answe to this equation...
is it 1 or 9?
Hope somebody here knows their maths
Originally posted by OmegaLogos
Explanation: Use Algebra...
6/2(1+2)=?
We all agree that we do BRACKETS 1st ok... [I was taught bodmas]
6/2(3)=?
Now lets go algebra on this and say that a=3
Rewritten ...
6/2(a) =?
Remove the brackets ....
6/2a=?
If a = 3 the answer MUST be 1
Because must resolve 2a 1st...
6/(2a) =?
6/(6) =?
6/6 =1
Personal Disclosure: My Dad was a statistician... for him 1 + 1 = 3 ...for large values of 1
SaberTruth's post on page 1 explains that in simplified technical terms!
Because as long as there are still brackets you must resolve them 1st regardless. Ask any maths teacher!
edit on 24-5-2011 by OmegaLogos because: Edited to fix name.
Originally posted by OmegaLogos
Originally posted by DaMod
Oi....
Please Excuse My Dear Aunt Sally
or
Parentheses, Exponent, Multiplication, Division, Addition, Subtraction....... That is the order in which you do equations....
6/2(1+2)=9
In kiddie terms...
1+2 = 3
so it's 6/2(3) or Six Secondths times Three
Explantion: Here is where you stopped using PEDMAS... there are still brackets/parentheses and yet your post goes on to start division! WTFH??? The (3) is still unresolved!
Personal Disclosure: If you don't follow the exact protocol all the time its not maths its fanatsy!
The rest of this is FANTASY according to the standard being used!
6/2 = 3... Yes because 6/2 is 6 divided by two......
so it's
3(3)=9
3 times 3 equals 9
I cannot beleive such a simple equation needed an entire thread to itself... Can we try a harder one now?edit on 24-5-2011 by DaMod because: (no reason given)
:shk:
Originally posted by stolski21
reply to post by iamhobo
the answer is 9, PEMDAS tells you that parentheses go first. So 6/2(1+2)=
1+2=3 then 6/2=3
3(3)=9
Please Excuse My Dear Aunt Sally
Please -- Parenthesis
Excuse -- Exponents
My ------- Multiplication
Dear ----- Division
Aunt ----- Addition
Sally ----- Subtraction
This next example displays an issue that almost never arises but, when it does, there seems to be no end to the arguing.
Simplify 16 ÷ 2[8 – 3(4 – 2)] + 1.
16 ÷ 2[8 – 3(4 – 2)] + 1
= 16 ÷ 2[8 – 3(2)] + 1
= 16 ÷ 2[8 – 6] + 1
= 16 ÷ 2[2] + 1 (**)
= 16 ÷ 4 + 1
= 4 + 1
= 5
The confusing part in the above calculation is how "16 divided by 2[2] + 1" (in the line marked with the double-star) becomes "16 divided by 4 + 1", instead of "8 times by 2 + 1". That's because, even though multiplication and division are at the same level (so the left-to-right rule should apply), parentheses outrank division, so the first 2 goes with the [2], rather than with the "16 divided by". That is, multiplication that is indicated by placement against parentheses (or brackets, etc) is "stronger" than "regular" multiplication. Typesetting the entire problem in a graphing calculator verifies this hierarchy:
If somebody writes a questions as
6 / 2 ( 1 + 2 ) =
then the answer is 9
BUT this may not be what the person meant!
IF they meant to introduce a fraction
so that everything after /
was on the bottom of the fraction
THEN we need to group together all of the question after the /
6 / [ 2 ( 1 + 2 ) ] =
Which does mean
6 2 ( 1 + 2 ) =
Again we understand that 2 ( 1 + 2 ) means 2 × ( 1 + 2 )
so let us introduce the multiplication symbol for clarity
6 2 × ( 1 + 2 ) =
The round brackets ( ) are grouping symbols
which indicate that
what is inside the grouping symbols should be treated as a whole
6 2 × ( 3 ) =
6 2 × 3 =
Do the multiplication on the bottom of the fraction
66 =
And then we do get the answer
1
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