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Originally posted by MegaMind
1 / 3 * 3 = 1 not one ninth. which is the equivalent of what many are doing.
Originally posted by MegaMind
Wrong. A * (B + C) = A(B + C)
BTW don't write any computer programs while thinking the way you do - it simply won't work.
Originally posted by GobbledokTChipeater
Originally posted by MegaMind
Wrong. A * (B + C) = A(B + C)
BTW don't write any computer programs while thinking the way you do - it simply won't work.
I use this way of thinking for solving this maths equation, not for programming. I understand the limitations of the compilers
People who type this into google and tell me adamantly that the answer is nine don't understand the limitations, though.
Originally posted by MegaMind
Or how about this?
1 / 3 * (3 + 0) = 1 or do some of you insist on the answer being 0.111111111 or 1/9?
Originally posted by MegaMind
Good luck with the math.
Originally posted by Red_xi
Originally posted by solargeddon
Originally posted by Red_xi
reply to post by solargeddon
WhoTF decided to put the extra bracket in, that isn't in the original sum, the sum is... 6/2(1+2)
There is no extra bracket used
Look at my calculators and tell me where you see an extra bracket?
Dude who's talking about your sum, god complex much ?!
If you go back to my first reply, you will see I refernce the OP, not you, so cool your heels.
Second I haven't even read the conclusion you came to, because SHOCK HORROR ! I haven't read the entire thread, just the gist, understandable given that I am not a troll !
Nothing wrong with a bit of healthy curiosity, oh and while I'm on it, don't know what country youre from, but perhaps this is a cultural issue, as from where I come from this is how the sum is solved.
Sorry, I'm not trying to bash you, was never my intention.
I guess your in the UK due to you mentioning GCSE's
I'm in England and this is definitely how it is taught.
Any way I'll be quiet now, I've said my pieceedit on 2-5-2011 by Red_xi because: (no reason given)
Originally posted by MegaMind
Let me ask you what is 1/3 (X + Y) distributed?
x/3 + y/3 correct?
or
(X + Y)/3
or
(X + Y)
Originally posted by GobbledokTChipeater
Originally posted by MegaMind
Let me ask you what is 1/3 (X + Y) distributed?
x/3 + y/3 correct?
or
(X + Y)/3
or
(X + Y)
Actually, I read it as
1 / (3X + 3Y).
Now you mention it this way, I distinctly remember this problem from my uni text books. If I can find it tomorrow, I will scan the relevant pages up and post.
Originally posted by MegaMind
Originally posted by GobbledokTChipeater
Originally posted by MegaMind
Let me ask you what is 1/3 (X + Y) distributed?
x/3 + y/3 correct?
or
(X + Y)/3
or
(X + Y)
Actually, I read it as
1 / (3X + 3Y).
Now you mention it this way, I distinctly remember this problem from my uni text books. If I can find it tomorrow, I will scan the relevant pages up and post.
You are violating the rules with that.
A (B + C) = AB + AC
A = 1/3
therefore,
1/3B + 1/3C
Basic algebra
same as (X + Y)/3 or (B + C)/3edit on 2-5-2011 by MegaMind because: (no reason given)edit on 2-5-2011 by MegaMind because: (no reason given)
Originally posted by IamBoon
reply to post by Mactire
I have a $200 calculator that says 9 is wrong. My cheap one says the answer is 9 though.
Originally posted by knightseifer
Mate, 1/(3B+3C) cant be written as 1/3B + 1/3C
Originally posted by MegaMind
Originally posted by knightseifer
Mate, 1/(3B+3C) cant be written as 1/3B + 1/3C
No kidding but I didn't write that did I?
1/3(B + C) = B/3 + C/3edit on 2-5-2011 by MegaMind because: (no reason given)
Originally posted by MegaMind
"A" can be any damn thing you want it to be!!!