reply to post by Slipdig1
Sea waters density is 1027kg/m3 not 1000kg/m3 so thats one mistake.
The density of surface seawater ranges from about 1,020 to 1,029 kg•m−3, depending on the temperature and salinity. Deep in the ocean, under
high pressure, seawater can reach a density of 1,050 kg•m−3 or higher.
All in all, this difference will not effect my calculations more than +/- 3%
There are 10000 cargo ships world wide able to take an average 15000 teu each. A Teu is around 24000kg 0r 24 tonne. This would weigh one in at
360 000 tonnes and 10000 would be 3 600 000 000 tonnes
The calculations that I used were for DWT, Dead-weight Tons, which is approximately 1,000 kilograms.
I *OVERESTIMATED* the Dead-weight Tonnage of the shipping fleets of the world, by multiplying the amount of Freighters in the world by the *MAXIMUM
So, in essence, the displacement I recorded in my calculations is *LARGER* than it would be with more accurate calculations.
How did you convert the square Kilometres to a measurement of volume by multiplying it by a measurement of weight?
Firstly, I used square meters.
Secondly, an area in square meters "A" can be converted to a "Sheet" of 1 meter in depth of the exact same number as the area measurements.
In other words... if you have an area that is 100 square meters, and you want the volume that this area would take up if it were 1 meter in depth,
you have 100 CUBIC meters.
The conversion from area to volume was so simple and self explanatory, I didn't really think to include it in my calculations, So... there it is.
I estimated the bulk shipping fleets at 282,361,250 metric tons, while you estimate them at 3,600,000,000, now that is around one order of magnitude
difference, but compared to the total volume of the oceans of the world down to one cubic meter, it is STILL very small... and thus my original point
Now, what we *COULD* do, is wax poetic about the minutiae of specific bulk shipping containers, bridge support displacement, Naval fleet sizes,
OR, we could realize that:
The oceans surface area is 361 million km squared
And since there are one million square meters in a square kilometer (1000 * 1000) then the surface area of the ocean in METERS SQUARED is
361,000,000,000,000 (361 Trillion square meters)
Now, to a depth of one meter, that gives us a total volume of:
361,000,000,000,000 SQUARE METERS * 1 = 361,000,000,000,000 CUBIC meters.
Multiplied by 1,000 kilograms per cubic meter (Or, if you prefer 1,027 kilograms per cubic meter, which, by the way, makes you even MORE wrong.)
Gives us a mass of 361,000,000,000,000,000 kilograms to 370,747,000,000,000,000 kilograms
Now, let's take the most conservative estimate (which is what I did... the one that makes you less wrong) of 361,000,000,000,000,000 kilograms and
divide that by YOUR estimate of the bulk shipping fleet displacement of:
Now, for this calculation we will assume the *TYPE* of tonnage that makes your point more correct, which would be the *TYPE* of tonnage that actually
has more mass, that being a Metric Ton (which is a full 10% larger than a long ton)
So, we have
370,747,000,000,000 tons / 3,600,000,000 tons
Which leaves us with a quotient of: 102,985.278
OR, 0.00000971012577 meters or... about 10 microns.
OR, about 1/10th the width of a human hair.
edit on 7-4-2011 by ErtaiNaGia because: (no reason given)