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# Unidentified Object Recorded By A DMSP Satellite

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posted on Jan, 28 2011 @ 08:35 PM

It is not a normal pictures.

The satellite is in a nearly polar, sun-synchoronous orbit with an
inclination to the equator at its ascending mode of 98.70 so it travels
basically north during half of an orbit and south during the other half. Its
altitude,A , is about (1,4) A = 461 nm (nm = nautical mile = 6077 ft = 1.854
km) and its orbital period is about l01.6 min = 6096 sec. The polar radius
of the earth, Re is about 3432 nm (6356 km) so it travels about
2(pi)(3432+461) = 24460 nm in each orbit (pi = 3.1416). The orbital
velocity, Vs, is therefore Vs = (24460 nm/101.6 min) = 240.7 nm/min or 4.012
nm/sec = 24,381 ft/sec (7.430 km/sec; Mach 21 if Mach 1 is taken as the
speed of sound at sea level). As it travels (nearly due north or south) it
scans perpendicular to the orbital track (i.e., nearly east-west) with an
on a detector. The output voltage of the detector at any instant is
proportional to the average temperature of the area that is within the
Instantaneous Field Of View (IFOV; the angular size of the area being viewed
at any given time) of the optical system at that instant.

posted on Jan, 28 2011 @ 08:36 PM

Where are you getting 12 seconds from?

The analysis states that it takes 0.56 seconds/revolution or 0.173 seconds for the sensor to scan from east to west

The time it takes to scan from east to west (or v.v.) is determined by a rotating mirror scanning system. The mirror rotates on a motor-driven shaft that is parallel to the orbit direction (tangent to the orbit). The rotation rate is 1.73 Hz, or 0.56 sec/revolution (3). This corresponds to 11.2 rad/sec (641 degrees/sec). Because the light rays bounce off the scanning mirror in such a way that the mirror is continually at 45 degrees to the centerline of the shaft and at 45 degrees to the incident and reflected rays, the scan rate of the IFOV is equal to that of the mirror rotation rate, i.e., the scan rate, SR, is 11.2 rad/sec. The total scan angle (as displayed on the photograph) is twice 55.6 degrees (0.97 rad) or 112 degrees (1.94 rad) so it takes 1.94 rad/(SR) = 0.173 sec for the sensor to scan from east to west (or west to east). (Actually the time was shorter than this if the scan width as smaller, as calculated below.)

posted on Jan, 28 2011 @ 08:44 PM

Ziggyproductions posted the 12 secs..
I was questioning it...

posted on Jan, 28 2011 @ 08:45 PM

Where are you getting 12 seconds from?

The analysis states that it takes 0.56 seconds/revolution or 0.173 seconds for the sensor to scan from east to west

The time it takes to scan from east to west (or v.v.) is determined by a rotating mirror scanning system. The mirror rotates on a motor-driven shaft that is parallel to the orbit direction (tangent to the orbit). The rotation rate is 1.73 Hz, or 0.56 sec/revolution (3). This corresponds to 11.2 rad/sec (641 degrees/sec). Because the light rays bounce off the scanning mirror in such a way that the mirror is continually at 45 degrees to the centerline of the shaft and at 45 degrees to the incident and reflected rays, the scan rate of the IFOV is equal to that of the mirror rotation rate, i.e., the scan rate, SR, is 11.2 rad/sec. The total scan angle (as displayed on the photograph) is twice 55.6 degrees (0.97 rad) or 112 degrees (1.94 rad) so it takes 1.94 rad/(SR) = 0.173 sec for the sensor to scan from east to west (or west to east). (Actually the time was shorter than this if the scan width as smaller, as calculated below.)

The total time required to create the AI is the time it took to create
the 22 scan lines which make up the image (see Figure 6): 21 x 0.56 + 0.007
= 11.77 sec. (This is the sum of 21 "spaces" between the starting points
for the 22 scan line plus the time it took for the 22nd scan line to cross
the AI. This isn't quite correct because of the sloping boundary of the
AI.)

There are many more factors that can effect the time as well. Its right around 12 seconds for the image we are looking at to be created, thats without considering the sloping boundry the object has.
edit on 28/1/11 by ziggyproductions05 because: (no reason given)

edit on 28/1/11 by ziggyproductions05 because: (no reason given)

posted on Jan, 28 2011 @ 09:28 PM
could be one of these:

posted on Jan, 28 2011 @ 09:39 PM

Could be a fixed object then...

posted on Jan, 28 2011 @ 09:45 PM

Could be a fixed object then...

Above the clouds and not moving??
Then what would the trails be.?

posted on Jan, 28 2011 @ 09:49 PM

Island?

Like in the pic toreishi linked to?

edit on 28/1/11 by Chadwickus because: (no reason given)

posted on Jan, 28 2011 @ 09:55 PM

The trails are nothing more than clouds, not contrails. believe me.

posted on Jan, 28 2011 @ 09:57 PM

Island?

Like in the pic toreishi linked to?

edit on 28/1/11 by Chadwickus because: (no reason given)

It cant be an island or any other body of land as it is the same temperature as the upper clouds. If it was an island it wouldnt be the color it is. The small rectangular shape in the object is the same color as the land mass below, if it were an island the whole object would be that blue color, not white.

*ETA-Whatever it is, is above the clouds and moving in speeds around 3-5 thousand miles an hour. I wish we could get some more anamalous pictures to compare and contrast. Thx for bringing this to our attention.

edit on 28/1/11 by ziggyproductions05 because: (no reason given)

posted on Jan, 28 2011 @ 10:16 PM
it's Laputa

posted on Jan, 28 2011 @ 10:21 PM

Well this is the conclusion of the analysis as well, hence the satellite theory.

But yeah, I have no idea either lol

posted on Jan, 28 2011 @ 11:03 PM

Well this is the conclusion of the analysis as well, hence the satellite theory.

But yeah, I have no idea either lol

I'm with you..

posted on Jan, 28 2011 @ 11:04 PM

Err seems ziggy edited...

posted on Jan, 28 2011 @ 11:10 PM

Err seems ziggy edited...

yes, sorry. i didnt realize you had responded. i'll fix it now...

posted on Jan, 29 2011 @ 12:15 AM
Interesting how it's clearly curving around, suggesting to me that it's rather small and moving at a slow pace. Most likely some kind of experimental aircraft or possibly a spy craft of some kind.
edit on 29-1-2011 by Neurolanis because: (no reason given)

posted on Sep, 27 2011 @ 07:41 AM
It is obviously a black project of types how can it not be more obvious, some absolutely ridiculous claims in here, an island what an island? for the love of god...

I believe its a black project "if not this" a later model

Known as technology demonstrators, these pioneering stealth aircraft remained top secret for years after their final flights before being declassified. They are categorised as black projects and operated from the secret Groom Lake test site in Nevada, USA, popularly known as Area 51. These groundbreaking designs tested low observable technologies and proved that stealth aircraft could operate deep behind enemy lines with a high degree of survivability. Together, they helped return the element of surprise to air warfare.

posted on Sep, 28 2011 @ 02:55 PM
Since everyone's discussing a Bruce Maccabee paper, I can't quite understand why he's not been named.

BM has his faults, but credit where credit's due.

posted on Jun, 16 2015 @ 03:35 PM
I believe the DMSP satellite was orbiting at 460 miles, so if this is true and the image is say a spy plane travelling at altitude of around 45,000 ft then it would be miles in size , or it was something closer to the DMSP satellite putting it in space and that's difficult to explain unless we can find what else manmade was up there.

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