a number you need
the beginning is prime
the middle is the result of dividing what you get times 110 by the beginning
the end is the beginning
if I'm thinking about this correctly, it would be equivelant to :
(x(110))/p = n
The middle part is really the only hard part, because there are technically three variables. At first i thought that x might equal n, but found that
to make p=110, which doesnt work obviously.
We know that p=prime so it could be 2, 3, 5, 7 as zsandmann said. Something we shouldn't rule out, is that "the middle" doesnt have to just be a
one digit number.
rearranging the the variable we can come up with :
x="what you get"
So if we can figure out what it is that "you get" then this will be pretty easy.
If x=12, then we can get the following
(p=2, x=12) the full number would be 26602
(p=3, x=12) the full number would be 34403
(p=5, x=12) the full number would be 52645
(p=7, x=12) you dont get an integeral number
The only thing i can think of if those are correct would be thread numbers, p=2 gives thread
and the rest are either dead zones or Mods only.
My algebra is a little rusty, so if I made any errors let me know
Hope this helps someone.