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Moon buugy footage question

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posted on Dec, 22 2010 @ 03:53 AM
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reply to post by Pilgrum
 



For the first 2 secs with a = 1.6 & u = 0: S=1/2.a.t^2 = 3.2m
On earth the same first 2 secs give an S of 19.6m


So six times slower than on earth as I stated..
Thanks..




posted on Dec, 22 2010 @ 04:21 AM
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reply to post by backinblack
 


So you'd see the problem with the earlier statement:

Note the 1.6m/s/s is acceleration, not velocity..
So you would expect an item on the moon would take 2 seconds to fall the first 1.6 meters...
Given it started with zero velocity...


2 seconds fall from standstill at 1/6 earth gravity results in a distance of 3.2m
1.6 metres at that gravity from standstill takes 1.41 seconds, not 2 but sqrt(2) in this case

yep I'm pedantic



posted on Dec, 22 2010 @ 04:24 AM
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reply to post by Pilgrum
 


lol, no problems mate..
I had it right at 0.8 meters in one sec and then forgot it was still accelerating..
You didn't mess up what I was saying at all..

It's still 1/6 the speed as on earth which was the point..

But I don't mind admiting when I make a mistake unlike some..



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