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Originally posted by turbofan
Originally posted by pteridine
I am happy to see that you now stand corrected regarding the erroneous figure you posted from LLNL. The labs are not infallible.
There is no correction. Your opinion is not a correction. Your opinion means nothing. If you would like
to disprove the LLNL data, feel free to provide some scientific sources. A debate requires that you
qualify your answers with proof, not dribble of text from your "thoughts".
Excess energy is not an excuse, it is just another failing of Jones paper and another reason he is unable to claim thermite.
He never claimed thermite. Get that out of your head. I already corrected you on the term "thermitic".
Thermitic does NOT mean thermite.
The products of elemental iron, and oxidized aluminium in spherical form however is the signature for an aluminothermic reaction. Please understand the difference. Jones proved an aluminothermic reaction, not thermite.
Got it after 6 pages?
We are looking at total caloric output. A match is much hotter than 1000 gallons of room temperature water. Guess which has more heat. Your statement "The fact is, an aluminothermic reaction such as Al/Fe203 can produce 1500'C by itself. The additional heat by combustion is irrelevent." shows that you have temperature and heat hopelessly confused.
Not at all. I've already linked you to an explantion of heat vs. temperature in a thread I posted weeks ago.
Proving once again, you don't read links. Energy release over time is what I meant by that comparison.
There is no confusion. Power is what this is all about.
You confirm that you do not know the difference between temperature and heat and then you assume a thermite reaction to prove a thermite reaction. Jones' paper provides no evidence of any reaction other than combustion and no spheres of iron are shown.
FOr the FOURTH TIME: The signature of thermitic reaction is not 100% iron.
A thermitic reactoin requires the reduction of a metal oxide and the oxidation of a fuel metal.
Do you understand this SIMPLE concept? This exactly why I wanted to step through these points before
engaging in a debate.
Now we must go backwards and do what should have been done first.
Pteridine, do you agree that the spheres are not supposed to 100% iron to show a thermitic reaction
as per any scientific reference, and Tillotson
Originally posted by -PLB-So why are you so upset when someone calls it a thermite reaction? Arn't you turning this into a game of semantics in order to avoid the hard questions?
Again playing semantics games. I of course mean the sharpness of the slopes of the peak. What on earth could I else be talking about.
Just look at the width of the blue peak of your home made graph, and write down how much degrees it spans
Now do the same for the original Tillotson graph.
I am sorry but I am not going to redraw this for you. You can just keep doing the simple test I wrote above until you do it right yourself.
So do you finally agree they are in the same order of magnitude? For example, in the Tillotson DSC the rise time is about 4 minutes. Just one minute difference from combustion. So proof, including sources, why a full combustive reaction can not take place in a time span of 2 minutes. You already accepted the proof it is possible in 5 minutes. Why not in 2?
Originally posted by pteridinein your "Jones' Dust Analysis: Comparing Known Nano-Energetics ( A Response to "Pteridine" )." Note the key on the figure is backwards; energy per unit mass and energy per unit volume are reversed. Yes, I am correcting a figure by a national lab . Refer to Jones' figure 30 for energetics. You are corrected, again.
thermite reaction whether it has gas generation materials mixed in with it or not. This is the reaction in question and changing the term does not change the underlying reaction.
Originally posted by turbofan
Wow, after 3 pages you were finally able to provide details so I could figure out what you were referring to.
All of this time, I thought you meant this graph as only since I posted it, did you bring up the 'key'
files.abovetopsecret.com...
So guess what, I agree with you...partially! The key is backward. However, that is not my problem, nor
my correction. Unfortunately for you, the X-axis label is correct and so are the values for heat of reaction.
We'll pretend the colour key is correct for now. Do you agree with the values?
thermite reaction whether it has gas generation materials mixed in with it or not. This is the reaction in question and changing the term does not change the underlying reaction.
I agree with that too...partially. So, the mixture is not classic Thermite due to the presense of other material...
so it's NOT "thermite". Correct?
If the aluminothermic reaction started as 2Al/Fe203 and ended as elemental iron, and oxidized aluminum
it would be considered a thermite reaction.
Do you agree?
Let's stop there and get your comments before moving forward on the rest of your reply.
Originally posted by -PLB-
reply to post by turbofan
Your poor drawing skills made the blue line look like Tiltsons graph. The peak is about 3 pixels wide, which corresponds to about 5 degrees.
I have been responding to your argument that the "sharp slope" is evidence of thermite (or whatever you like to call it, not that interested in your semantics game), not the argument about the entire width of the exotherm (I can go into that one too if you like, as you have not supported that either with any source). And I am, to my knowledge, consistently referring to the width of the peak, not the width of the exotherm (if I did it was a mistake). The combustion DSC and the ones of Jones do show similar sharpness in the slopes. Of course the DSC of crude oil and Jones unknown sample are not exactly the same. I only used it as example of combustion showing a sharp slope. Nothing more.
As for your width argument, if a small width of the entire exotherm indicates a thermite or explosive reaction, Tiltsons DSC fails to pass this criteria.
Originally posted by turbofan
Only 'god' knows how you thought Tillotson's graph was drawn when we were totally discussing Jones trace
vs. your oil trace.
Thanks for wasting all of that time though!
Well, consider yourself off-line in this discussion.
YOu obviously don't know what you're talking about as you try to relate one part of the exotherm trace
to prove your case.
Too bad, so sad but the energy over time is figured by the entire exotherm trace...not ... just... the
"ignition slope"or whatever YOU want to call it...
Not even Pteridine will agree with you on that.
PLease stay out of this debate.
edit on 19-12-2010 by turbofan because: (no reason given)
Originally posted by pteridineAs to thermite and aluminothermitic reactions; the reaction between aluminum and iron oxide is called the thermite reaction whether it has gas generation materials mixed in with it or not.
The height of the peak; the slew of the trace; the duration between Temp 2 -Temp 1 indicate the amount
of energy released.
Pteridine, do you agree that a more narrow exotherm indicates a reaction which is closer to that of an explosive
rather than combustion? Do you also agree that a sharp slope (positive , or negative) indicates the speed of a reaction closer to that of an explosive rather than combustion?
In the figure below (From Tillotson's paper), the scientists conclude that thermitic reaction begins at 500'C,
and the exotherm centers at the 530'C point along the x-axis. Even though there is presence of heat over the
control temperature at 400'C through 500'C, this section is excluded as the 'active' region
Finally, do you conclude that the quick drop, and slope of the exotherm indicates that the available energy
was spent in quick fashion and more closely resembles an explosive event, over a combustion event?
Originally posted by pteridine
reply to post by turbofan
Of course the reaction will take place. I never said anything else. The problem has always been the presence of an unknown amount of combustion. That must be ruled out to measure the energy from non-combustion reactions.
Originally posted by turbofan
Originally posted by pteridine
reply to post by turbofan
Of course the reaction will take place. I never said anything else. The problem has always been the presence of an unknown amount of combustion. That must be ruled out to measure the energy from non-combustion reactions.
What does it matter if material is combusting if you admit that the thermitic reaction will take place whether
air is present, or not?
The excess heat is of no concern as you admit that redox takes place in the presence of air.
This proves an aluminothermic reaction beyond all doubt as the oxygen in the air will NOT react with the bonded
Iron Oxide and Aluminum.
Therefore the only way to reduce the iron oxide is for the aluminum to attract the oxygen.
The presence of elemental iron is the proof as is the oxidized aluminum.
Originally posted by pteridineWhat elemental iron? Jones never claimed elemental iron. Stick to the topic.
You are assuming that the thermite reaction is occurring but that is what you have to show.
In this reaction iron (III) oxide is reduced to metallic iron by aluminum. It is reported that the reaction will reach a temperature of about 3000°C, meaning both reaction products are molten (mp Fe = 1530°C; mp Al2O3 = 2030°C).
What elemental iron? Jones never claimed elemental iron.
Originally posted by turbofan
Hence, the discussion about heat is pointless.
This debate is over once you understand that air will not react with the 2Al + Fe203 bond!!!!!!!!!!!!!!