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Originally posted by -PLB-
reply to post by turbofan
The only person dodging questions is you. The question you ask is ambiguous anyway and irrelevant for the issue at hand. You are just creating smoke screens in order to avoid admitting those sources that support your opinion, don't exist.
So again, show sources that support your claim that the exotherm can't be combustion, or admit its just your opinion.
Originally posted by turbofan
Tell me which line is most explosive.
Originally posted by turbofan
Can you tell me which one?
Originally posted by -PLB-
Originally posted by turbofan
Can you tell me which one?
Lets change the question. Can you tell from those lines if there is an explosive reaction at all? If so, how can you determine this, and give me some sources that back this up. And if you can't tell if there is an explosive reaction at all, what is the point in asking which one is more explosive? Its just a nonsense question.edit on 31-12-2010 by -PLB- because: (no reason given)
Originally posted by turbofan
PLB, you are overthinking this HYPOTHETICAL question.
We know by known sample that the blue represents the exotherm of nano-thermite. We know that nano-thermite
is explosive in nature.
The dark blue line is therefore our benchmark.
Now, please tell me which line is more explosive than the dark blue line.
Do you think it's the red line? The green line? The purple line?edit on 31-12-2010 by turbofan because: (no reason given)
Originally posted by -PLB- Why can't the DSC trace show regular combustion and back it up with sources. Well, you are not really dealing with it, but rather ignoring it and respond with irrelevant issues.
explosive reaction, then we can also assume, by definition, that all these reactions took place within 1 second. It is impossible to determine which was "more explosive", as the curves show the energy release in the order of minutes, not seconds.
Originally posted by turbofan
I don't know why I bother wasting my time debating anonymous people on the internet. I really don't.
Even with diagrams and basic questions, you are still not able to follow along.
It CANNOT be REGULAR combustion becuase the material is consumed at a faster rate than a KNOWN EXPLOSIVE.
How simple and easy is that ?
It's black and white, yet you are not able to answer this basic question. It's unreal.
THis was only to show and prove that peak has absolutely NOTHING to do with showing that a material is
more explosive than a known bench mark.
More to the point , this quote yet again highlights you are debating a topic you have no idea about.
YOu continue to relate reaction time of the explosion with the DSC trace!
I have shown known traces of explosives. Explosives which react within MILLISECONDS, yet you cannot
grasp that the reaction time of an explosion is not the same as heat flow measured in "minutes".
So you keep repeating. With no sources, or anything to back it up.
Can you explain precisely how you determine how fast the material was consumed, and can you give an exact time?
In fact, I very well grasp this concept, and therefor I conclude I cannot determine if a sample is (more) explosive from the DSC curve.
Originally posted by turbofan
If the heat is generated faster, and removed quicker than something you know is an explosive
IE: RDX, PETN, Thermite
Then the sample you are testing is explosive.
Time is what you measure; not peak.
The ignition slope: Explosives generate heat rapidly. They react quickly and release all of their energy
quickly. In milliseconds. Explosives generate a steep slope because of this.
If your test material is generating a steep slope, it too is generating heat rapidly.
The width of the curve: The time/duration of the heat above the referenece point (exo) indicates heat
flow.
If your test material is producing all of its energy within a more narrow exotherm than a known explosive,
it too must be more explosive.
The decay of heat: due to the fact that explosives use up all of their energy instantly, you will observe
a quick drop in heat after peak. This rapid decent in the slope, and quick decay in heat indicates nothing
is left to "burn". Heat is removed.
If the test material has a sharp drop after peak, it too has used up all of its energy and nothing is left to 'burn'.
Heat is removed quickly.
Known explosives whether thermitic, or having some sort of 'combustible' organic exhibit ALL of these
characteristics.
Jones' test sample exibited ALL of these characteristics.
Therefore, Jones' sample is MORE EXPLOSIVE than a known nano-thermite.
Paint cannot do this! If you still believe that, please post a link to known study of paint in a DSC machine!!!!!!!!!!!!!!!!!!
Otherwise leave me alone!!!!!!!!!!!!!!!!!1111 !!!111
Originally posted by pteridineIt is apparent that you have little knowledge of chemistry
Originally posted by Cassius666
reply to post by -PLB-
Well what behaviour would that protective paint exhibit if the same tests were performed on it. If a sample of the protective paint is run through the same tests and we have a match, case closed, if not....
Here is my question to anyone who can answer this, if possible.
What is the chance of taking one of these dust samples to an FBI forensics lab and them telling you exactly what's in the dust? I would think that they have a data base for just about every known material.
Is this idea even conceivable, and if so, what would it take to arrange this?
Originally posted by turbofan
PLB, forget it dude. Do some research on DSC machines and what you are looking at before you
enter a debate. Jones' duplicated Tillotson's environment and all of your other concerns are covered
in the data.