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This is a worthwhile subject, and I have spent my share of time on it. I remember when it was first brought up and I thought it was bunk. What I thought was bunk was this video where the guy puts these red arrows in the sky, end to end and says the plane should have been "here". What I did was watch the buildings and how they moved in relation to each other, and could see that the whole time they were moving in an arc so that the camera had to keep turning in relation to the body of the helicopter in order to keep the WTC in frame, so that changed where the far edge of what would have been visible. That was what I thought and did not go further into it at the time, other than to make comments on people's videos to tell them to look at that.
A plane traveling at X mph would be approximately Y distance away from the impact point that would be further out than the camera's field of vision.
Originally posted by Monsieur Neary
Originally posted by Esoteric Teacher
if the aircraft was calculated at moving at a speed in excess of 500 miles per hour, and there is 9 seconds from the wide shot to the impact, i think.
math is not my subject.
so if a plane is travelling at 500 miles per hour, how much distance does it travel in 9 seconds?
how far out does that wide shot cover.
answer these questions, and maybe ....
If those numbers are correct, and if my math is correct, it would be 1.25 miles. If in "excess" of 500 mph, than the distance is further, making it more likely it is out of the frame. Hard to tell what the distance is in the zoomed-out part of the shot at the beginning. Also, the plane could be in the shot but just hard to see due to the video resolution.
edit on 15-9-2010 by Monsieur Neary because: changed "there" to "in the shot"
edit on 15-9-2010 by Monsieur Neary because: clarified distance