Any one have any idea? g = s x v²

reply to post by masonwatcher

---

Not me. Wolfram Alpha.

But I can generate a vaild physical equation out of this.

With x haveing the unit s^3 / (kg*m) you could write x as time / force
x = t / F ?

But t / F doesn't makes much sense however dt / dF would make sense.

x = dt/ dF

So place it into the equation:

g = S * dt/dF * v^2

and solve for F (Force):

F = Integral S(t)*v(t)^2 / g(t) * dt

here the units add up and this therefore is a valid candidate for a physical equation.

Edit to Add:

p.s. note S is position depend and on a movement that is time depend S become time depend thats why I write S(t). The same with g.

p.s.2. of course S = solar constant, g = gravity, v = velocity as given by the other thread. But don't ask me about the sense of that F !
Remarkable with a constant velocity you can generate an ever growing Force with this formula.


[edit on 19-6-2009 by g210b]

reply to post by dannyfal

---

It's a between threads thread.
Not for being too serious about but keeping the mind ticking over.

Look at the replies.Bringing intelligent discussion aside of the original.

Yes other kind of replies as well but they as in any other thread can be ignored.


[edit on 19/6/09 by gallifreyan medic]

that is the first thought that came to my mind too... again i'm not tryin to beef with anybody and i understand that it is an intellectual excercise but...

isn't it just something that is MADE UP? by a delusional cult leader? why am i the only ATS member that thinks there is no solution to this.

Dude's a fool. Check out my response.

His formula doesn't work.

Where did I saw something about an spanish blog in blogspot.com?

most likely yes.



dunno don't know that man.




You are for sure not the only one. The most will think that and this includes me.

But see one thing it is not proven to be made up before you have ever spend some thoughts into the subject and it is a fun and challenging thing to spend some thoughts in impossiblenesses. At least I like that.


[edit on 19-6-2009 by g210b]

Yes. I think he was running a blog.



I personally don't believe his story, but the formula is interesting for me.

[edit on 19-6-2009 by Spinotoror]

After having scanned this entire thread, although there seemed to be a few posts by members who actually do know some basic physics, I was pretty suprised to see knobody pointed out the following obviously similar eqn -


All the OP really did here was replace m/2 with S, and replace E-sub-k with g.

Why ?

Well, he got my attention as well as everybody elses ...

It's the same exact equation as E=mc², except E is g, s is m, and c is v.
Same exact equation with different variables...

Edit: now it seems he's not referring to the "x" as a multiplying sign. He just made this post:




So I don't even think this equation can be confirmed if what he just said is true.

[edit on 6/19/2009 by bl4ke360]

reply to post by bl4ke360

---

I am no expert by any measure but I have dibble dabbled in a number of subjects for fun; with a couple assumptions I thought it may have something to do with string theory and motion through space.

It does not make sense. Just looking at the units, the constant has nothing to do with what he claims.

g=Sxv^2

Looking at the units, ignoring magnitude of the variables, one can determine what units S is.

m=meters, s=seconds
acceleration, g, is measured as m/s^2
velocity, v, is measured as m/s .: v^2=m^2/s^2

so S=g/v^2
.: S's units=(m/s^2)/(m^2/s^2)=1/m

So basically the sun constant, S, is supposed to be the multiplicative inverse of distance.

"where S is the Sun Constant, which gives spaceships its “fuel” as the energy any planet receives for every cm² each second from the nearest star, depending on the planet angle from the Sun and, consequently, its AU"

[edit on 19-6-2009 by Nomnoms]

reply to post by Nomnoms

---

Thank you. I will quote it and paste it on his thread.

Umm i have no idea what g is? Could you have possibly misinterpretted a letter of the greek alphabet?

But in mechanics "V" stands for velocity and "S" stands for displacement (distance from origin).

so

The Unknown G = Velocity squared x Displacement which can actually be written SV^2

G= Gravity? Something to do with space? How large the force of gravity is when an object reaches a certain velocity? or has travelled a certain distance?

Tell him this...

If S is a constant then your saying that distance is what is relative in our perceptions, and not velocity.

Thank you for your posts.

Its kind of fizzled out know the wanting to know upon another thread.
Well actually its a case of the outed out now.

reply to post by getreadyalready

---

I don't know if any of you have seen this video, but it ties in some of what you have brought forth here, in regards to leaving the "spaceship" in place and bending time space around it. If someone has this linked already, my apologies, but if not, it could answer some of the questions. (unless everyone here is a naysayer stuck in conventional wisdom)

Google Video Link

It is a little long, but well worth the time, not only for this thread, but anyone thinking outside the preverbial box that we have been spoon fed.

Still learning how to insert goodies, so please be patient with me if this video does't show up.

I think that the equation tells us about time.

g = time/second

The equation g = s · v² really means g = s,s

In other words (g) is mass or a object = second, second

Where g = s

You cant have time or changes without (g).

Edit:
g = s ?

Geometric figure: a line

Properties:
g-intercept = 0
s-intercept = 0
slope = 1

solution to variable s is: s = g

Time = matter

Edit:

The equation g = s (v v ):

{g = s,v^2} where g = s and v^2 = Plot[v^2, {v, -1.2, 1.2}] on a graf.

v^2 = ({v^2}/.g)

{v^2|g = s} = 0 when {v,g,s} = {0,33/10,33/10}

{0,33/10,33/10} = 0+33/10+33/10 = 6.6 which are Spherical coordinates (radial, polar, azimuthal): r = 4,6669, θ = 45°, φ = 90°

This is a sphere at its very birth in time because the variable (s) or (g) cant be 0. Because s = g.



[edit on 27.06.08 by spy66]