Kaifan, Beamish and all the “skeptics”
Here’s your formula Guides use to travel
g = S x v²
where S is the Sun Constant, which gives spaceships its “fuel” as the energy any planet receives for every cm² each second from the nearest star, depending on the planet angle from the Sun and, consequently, its AU
Ly-on
Hmm the description of S make it sound like the sloar constant.
The solar constant specifies the light energy per area you get each second
at the distance 1 AU (Earth-Sun Distance) from the sun.
The value is 1367W/m^2 = 1367 J/(m^2*s) = 1367 kg / s^3
Now this value has a direction(vector) ..from the sun outward and you can only get that amount of sun energy with an area that stands normal to that direction. If you tilt the area you have to take the angle into account.
But this is for a smal flat area like a solarpannel.
For the whole planet the planet angle doesn't play a rule. When you want to know the total energy the earth gets from the sun radiation then you simple can calulate with the intesection area of the whole earth.
So talking about the planet angle in connection with this sounds a little strange to me.
Now we have no clue what g and v stands for.
My guess would be that v is the velocity which is a vector.
Then I guess that the meaning of s x v
with s as vector and v as vector is a corssproduct.
x is often used for crossproduct.
If we now check the units we have kg /s^3 * (m/s)^2
which gives you the unit kg * m^2 / s^5 for g which is byway then also a vector and stands normal to s and v
with this g then can not be gravity
now kg*m^2/s^5 is a unit that doesnt really makes sense for me.
The best thing you could do with that is to split it into (kg*m^2 / s^2) / s^3 which would be an Energy density but not in room but in time (s^3).
Now before you think this is high tech ..you should se ethat the solar constant with the unit kg / s^3 would be interpreted by the units the same way thats then a mass density not in room but in time.
Which for sure is very unfamilare to us.
So when my asumption about s and v are correct then I have no clue what this result g shall be.
One last remark maybe..with this formula you best have the velocity orthogonal to the sun radiation for a maximum g.
so.. dunno what to think about this.
edit to add:
what speaks against the corss product is that it is not
s x v but s x v^2
[edit on 18-6-2009 by g210b]




