reply to post by Agent Venom
Hello agent venom,
At first I was quite convinced by this theory but I felt something was wrong and I found out what.
You made quite some critical errors in the formula’s.
First, you don’t need the gravitational pull at all for calculating the escape velocity.
For M you have to fill in the mass of the planet that is orbited, in this case the sun.
The mass of the orbiting planet or satellite, in this case nibiru is not implied.
You also filled in km’s instead of meters.
Check Wikipedia and you’ll see that the mass of the orbiting satellite or planet doesn’t have to be filled in and why.
en.wikipedia.org...
you made mistakes though in the first formula, big ones, I’m sorry.
For gravitational pull you used km’s instead of meters.
If you fill in meters, this gives F=1,1202 X E25 N (not N/s)
If I recalculate the outcome of your first formula it gives F=1,1202 X E31 N
Now idea how you achieved the …E44 value.
F = G x Msun x Mnibiru / r^2
F = 6.67 x 10^-11 x 1.9891 x 10^30 x 1.8986 x 10^27 / (150,000,000 x 1000)^2 = F=1,1202 X E25 N
Now the escape velocity:
V = (2 x G x Msun / r)^0,5
V = (2 x 6.67*10^-11 x 1.9891 x 10^30 /( 150,000,000 x 1000))^0,5 = 13304,5 m/s.
Making km/u out this: 13304 x 3,6 = 47896 km/u.
Per day this is 47896 x 24h = 1,149,512 km
This is quite reasonable.