e=mc2 = wrong? Photon mass = 0 yet has energy? Need help Please.

reply to post by lordtyp0

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I think your explanation 2 males sense up to the point you start discussing photons.

Regarding your explanation 1, why not just say E=mc^2 describes how much energy you get out of a mass when you convert mass to energy?
The Sun converts 564 million tons of hydrogen into 560 million tons of helium every second. Where does the missing 4 million tons of mass go? that's released by the sun as energy. that's what e=mc^2 is all about. I think your photon comment has little to do with the equation e=mc^2 because the formula has mass in it and as you correctly point out, the photon is massless.

I would say that for a massless particle, the formula e=mc^2 is not wrong, it's just not applicable, since there's no mass. So you have to look for other formulas to describe the photon. And mass isn't the only form that energy can take, that's another reason why the formula simply doesn't apply to massless particles.

[edit on 4-11-2009 by Arbitrageur]

reply to post by Arbitrageur

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This is going to sound strange, but 0 is still a value in an equation. When applied to zero mass it essentially any amount of energy will accelerate the particle to maximum velocity (c). The inverse of that is obviously: as mass increases it requires more energy to affect it.


That is basically what I was trying to convey, but yes, it is a clunky way of doing it, feel like I am babbling right now as well. Hope it makes sense.

You are correct about zero being a valid value in an equation. You are incorrect about the mathematics of how the equation works when zero is inserted.

substitute zero for m in the equation E=mc^2 and you get E=(zero) x c^2

which is correct because it says the amount of energy you can extract from zero mass, is zero.

The equation says nothing about the maximum velocity of a photon, how much energy it takes to accelerate the photon, or anything else you have attributed to the equation as it relates to a photon. The only thing it implies about a photon, is how much mass you could possibly get if you were somehow able to convert the energy of the photon into mass, by re-arranging the equation into the form m=E/(c^2)

Like I said the e=mc^2 is is otherwise not applicable to photons, but the applicable formula for photons is instead E = pc :

Photons



And you'll have to see the source for the rest of the equations that apply to the photon because I'm too lazy to copy them here for you.

Lastly to further prove you're barking up the wrong tree trying to relate the E=mc^2 equation to the photon's travel at the speed of light, note that the term in the equation other than energy and mass is NOT the speed of light, it's the speed of light squared! So using your arguments why wouldn't imparting energy to the photon make it travel at the speed of light squared? Obviously it doesn't but that's just further proof it's the wrong equation for what you are trying to do.

E=mc2 is just an equivalence equation; mass & energy are the same thing.

Just understand that we don't understand, hence the billions pent on LHC to discover the unknown.

no it wouldnt of changed, becuase the scales have now gained mass througuh reaching such a speed, as well as yourself.

reply to post by TheRedneck

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Thanks for the link. I am going thru it now. Does it not make your head hurt?

reply to post by lordtyp0

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From a beginner ATS member, I thought your explanation was thorough. I have also been looking at Nassim Haramein's Grand Unified Theory videos on YouTube.

www.youtube.com...

I think there are about 45 videos on Nassim. I have watched about half of them so far. FASCINATING Stuff. He covers Einstein's theory, quantum physics, sacred geometry...very comprehensive!

Photon energy comes from the frequency.
Frequency of what.
The ether.
The ether has been shown to exhibit pressure waves, see Tesla
"Experiments...", and thus can interact with matter.
We can't talk about such things as the apple cart will be upset.
Ed:
en.wikipedia.org...
E^{2} = p^{2} c^{2} + m^{2} c^{4}.
but see the following lines:

E = hbar omega = h nu = h c \ lambda

p = hbar k,

but frequency is c/lambda so E = h f

So ether frequency gives you the energy for the UFO.
All done by Tesla long ago.
ED+: A little check of the momentum,p, formula you
see how instant velocity is obtained by the UFO.
So with 2 p's, up and sideways you have the UFO propulsion.

[edit on 11/6/2009 by TeslaandLyne]

[edit on 11/6/2009 by TeslaandLyne]

Looks like I was thinking of the relativistic version of F = MA. Probably just associated due to the relativity function. I was thinking since e=0 then anything >0 would propel to max velocity.

The excerpt below is from: math.ucr.edu...
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The concept of relativistic mass is neatly encapsulated in the expression F = d(mv)/dt, where m is relativistic mass. This says that an impulse F dt causes an infinitesimal increase in a body's relativistic momentum mv.

Besides this definition and use of relativistic mass, we wish here to write down the relativistic version of Newton's second law, F = ma. In Newton's mechanics, this equation relates vectors F and a via the mass m of the object being accelerated, which is invariant in Newton's theory. Because m is just a number, in Newton's theory the force on an object is always parallel to the resulting acceleration.

The corresponding equation in special relativity is a little more complicated. It turns out that the force F is not always parallel to the acceleration a. We can express this fact using matrix notation. Let m be the rest mass, and v be the velocity as a column vector, whose entries are expressed as fractions of c and whose magnitude v is the speed as a fraction of c. Let vt be the velocity as a row vector, and let 1 be the 3 × 3 identity matrix. As usual, set γ = (1 – v2) –1/2. The relativistic version of F = ma turns out to be

F = (1 + γ2 v vt) γ m a

and

a = (1 – v vt) F
——————————
γ m

So defining mass via force and acceleration isn't as simple as it was for Newton (although it is simple, in principle, to define the mass as relating impulse and momentum increase, as mentioned a few lines up). Nevertheless, the three components of the two expressions above share a factor of γ m, and the rest mass m only ever appears in both expressions accompanied by γ. The acceleration is not necessarily parallel to the force that produced it, and it's not hard to see from the above equations that it's easier to accelerate a mass sideways to its motion than it is to accelerate it in the direction of its motion. This is how relativity reproduces Lorentz's original concepts of longitudinal and transverse masses; they are actually contained in these equations. The directional dependence that the newtonian meaning of mass has now taken on is neatly contained in the matrices 1 + γ2 v vt and 1 – v vt, and the remaining factor γ m is the relativistic mass. Taking our cue from the equations like this, to isolate quantities that might prove useful, is a powerful tool in mathematical physics.
reply to post by Arbitrageur

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Good equations, but if a photon is massless, then accelerating it can't define its mass anyway. And are photons accelerated at all? Or do they leave the source traveling at the speed of light instantaneously with no acceleration at all?

Teslaandlyne, the frequency that determines the energy of the photon is the photon's frequency. If it's a photon for red light, it will have less energy than a photon for blue light since blue light has a higher frequency and is therefore more energetic than red light. That is independent of the frequency of the ether if there is such a thing, (which Einstein said there isn't).

reply to post by Arbitrageur

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Sorry about that.
I got old school, Tesla's 'medium', into an explanation about the
new school of Einstein. Tesla had a short discussion about light
before the photon decree of Einstein perhaps as Tesla's interest
was making light in air, gases and in the medium of a highly
evacuated bulb. Tesla use vacuum equipment to take everything
out of a bulb so there was nothing left. The nothing lit the bulb.
So naturally Tesla says something is left inside to light the bulb.

Tesla continued to push the nothing, or medium, with high pressure
coils (low power oscillations that grew higher and higher pressure)
to transmit electrical pressure and force in some cases.
An electric induction process not magnetic in any way.
So far what can deduce from the Tesla research controversy.
So the photon analogy seems to fit in some way.

Have you got a source and link about that? He probably wasn't able to draw a perfect vacuum for starters. Even with good vacuum equipment something is left, the better the equipment, the less is left inside, but it's probably not "nothing".

The 'nothing' refers to the 'ether' which does not exist per
Einstein as I was told on ATS and many many forums.
So a nothing lit the bulb. An inside joke, sorry.
So here is how:

The 'medium' whatever (or nothing ) moves physical mass of the left
behind atoms and knocks them up against the glass and lights up
from high voltage and high frequency one way pulses. This is very
important since ac becomes one way at high voltage and frequency
and even more so at 1/4 wave cycle impulses. At high frequency
taking each 4th turn is only helping the flow. The pounding and brief
relaxation involves physical and electrical lighting and heating
of the left over gas atoms against the glass bulb.

This is not electron flow from a TV tube that has electrons available
around a heated filament to be drawn away by high voltage.
The high voltage pushes the carriers in the medium.
Something like bar magnets push each other through a medium.
Thus a flow in the medium exists. A pressure flow.

Tesla used the mechanical vacuum means at that time but mentioned the
need for electrical means which he might have noted in his
"Colorado Springs Notes" as well as in his "Experiments.." document.
His locked up inventions should have this electrical vacuum machine and
only those allowed to use them profited. So my guess is there might be
electrical vacuum machines around today. One might suspect as well
that the high vacuum is used in the fabrication of saucer parts.