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... The speed associated with doppler shifts that are visible is so fast that you will be 'blown apart'.
z = Δλ / λ0
v / c = ((z + 1)^2 - 1)/((z + 1)^2 + 1) source
If you want to shift the frequency 50%, then Δλ / λ0 = 0,5, solving for v gives:
v = ((0.5 + 1)^2 - 1)/((0.5 + 1)^2 + 1 ) c
v = 0.38c
That is really really fast.
Originally posted by smirkley
The observer (with measurement devices, since the human eye is at best good for seeing a frame of video at 1/2 of a second without 'blending' the image, more on this in a sec) would see the rainbow oscillating between infrared and ultra-violet?
Since the eye is not a fast 'frame grabber' so to speak, it is also possible that the observer without equipment and just visual observation, could get 'stuck' in a visual 'refresh rate' of a harmonic of the oscillation frequency, and the mass may appear to be a steady color in the spectrum reflected?