NASA Scientist Fired - Promises Disclosure, page 41
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reply posted on 3-12-2007 @ 11:08 AM by weedwhacker
reply to post by Tuning Spork



Tuning Spork,

I didn't really have a question, sorry that wasn't clear. I was commenting on the fact that reading the back-and-forth is interesting.


reply posted on 3-12-2007 @ 12:01 PM by weedwhacker
Originally posted by buddhasystem
SO, even IF the Moon were that massive, would not the orbit and behavior of the Moon that has been observed and recorded for thousands of years betray this? And I'm just supposing a Moon that is .25 percent of Earth's mass...it's hard to fit .64 percent into the facts of years of observations....just my opinion....


Greetings TJ/WW,

this argument has been made by me before, and of course what I heard back were accusations of being closed-minded and a few buckets of vitriol. I hope your fair post will get a better reception from the "believers".


Thank you, buddhasystem,

I see you pulled only a portion of my original post (I still don't know how to do that!) but I think you did it to not run afoul of the rules, so I understand.

I think it is an important question, that is (i.e.) 'How could our Moon be that heavy? If the Moon is .64g, that is incredible. Mars is, we're told, slightly more than one third the diameter of Earth...I would like to know the exact g on Mars.

Somewhere else (another thread) I postulated that our Solar System has THREE rocky planets that are within what would be considered the 'habitable' zone, based on our star's (the Sun) composition and radiation output. Actually, I didn't postulate that fact, what I meant is, as we try to discover other planetary systems, we first see the 'wobble' of the host star, and infer the existence of a large planet. I'm just suggesting, our system has THREE rocky planets!! In different eras, all three could have been conducive to life as we know it. Is this unique? I doubt it.


reply posted on 4-12-2007 @ 10:30 AM by JimO
More claims:

Russian Media Publicity Part Two: Updated 11/26/07!
www.enterprisemission.com...

Moskovsky Komsomolets
www.mk.ru...
22.11.2007 01:00 aticle
Дмитрий Алексеев, Наталья Степанова

Q&A BETWEEN 'MK' AND RICHARD C. HOAGLAND
And now, the moment we've been waiting for... the actual Q&A "Moskovsky Komsomolets" sent to me, along with my answers. This is where the real 'meat' of our article comes into play, as much of this content was edited down for publication [JEO: including all references to Oberg]:
nip>

MK: Are you afraid that NASA or USA government could be after you because of the fact that you've disclosed this secret?
nip>
Getting back to the thrust of your question, we have seen one case of open retribution against Dr. Johnston. This appeared in the sad efforts of one former NASA contractor, James Oberg, who is now a science consultant for the NBC network.
Oberg got Dr. Johnston dismissed from his volunteer position in a current JPL educational program, strictly because of his public testimony in "Dark Mission."
Oberg felt that Dr. Johnston was criticizing NASA’s actions during and after the Apollo missions, and convinced Dr Johnston's boss, Kay Ferrari, to immediately fire him and remove all traces of his service from the public record online.
Any further examples of harassment, threats or intimidation towards either Dr. Johnston or me would simply politically confirm what we've been saying for eleven years:
That NASA has been officially hiding the REAL Moon all this time.


reply posted on 4-12-2007 @ 11:06 AM by johnlear
Originally posted by weedwhacker



Sorry, the math confuses me here...if the 'Neutral Point' is 43,495 miles from the Moon, and that is approximately one fifth to one sixth the distance between the Earth and the Moon...how is it not true that the Moon's gravity/mass is approximately one sixth of the Earth's?


What we are doing weedwhacker is figuring the moons gravity relative to earth using the Bullialdus/Newton inverse-square law.

The inverse-square law (Bullialdus/Newton) is any physical law stating that some physical quantity or strength is inversely proportional to the square of the distance between them, specifically, the gravitational attraction between two massive objects, in additional to being directly proportional to the product of their masses, is inversely proportional to the square of the distance between them.

Therefore using the following values:

Re = radius of the Earth = 3,960 miles
Rm = radius of the Moon = 1,080 miles
X = distance from the Earth’s center to the neutral
Point = 200,000 miles
Y = Distance from the Moon’s center to the neutral point = 43,495 miles
Ge = Earth’s surface gravity
Gm = Moons surface gravity

Since the forces of attraction of the Earth and the Moon are equal at the neutral point, and we know the neutral point from Wernher von Braun's statements and Michael Collin's (Apollo 11) "Carrying the Fire" and Gene Cernan's (Apollo 17) book, "Last Man on the Moon", the inverse-square law yields:

Ge (Re²/X²) = Gm(Rm²/Y²)

Gm/Ge = Re²Y²/Rm²X²

= (3,960)2 (43,495)2/(1,080)2 (200,000)2

= .64

Therefore, Gm = .64 Ge

So the gravity on the moon is approximately .64 that of earths gravity or almost two thirds. Now we understand why the Apollo astronauts were making those pitiful 18 inch hops on the moon. It should also be obvious why they tired so quickly.

If the moon’s gravity was in fact, one-sixth that of earth or approximately 16.66% we could work the problem in reverse and come out with a neutral point from the moon of about 24,000 miles. There is no evidence that the neutral point is that close to the moon.

That the gravity on the Moon is one sixth that of earths is one of the biggest con jobs in the history of mankind.


reply posted on 4-12-2007 @ 11:58 AM by JimO
Originally posted by johnlear

Since the forces of attraction of the Earth and the Moon are equal at the neutral point...



Your fundamental misconception is that you treat these forces based on an 'Earth' and a 'Moon' that are static, locked in place by some alien force,
not free to move or fall or ... orbit each other, as they really do.

Consequently, the 'neutral point' to you is merely a matter of 'gravity', and not a sum of ALL forces actually acting on an object.

This is decades out of date -- but prior to the space age, that's how most science writers (and scientists) thought, merely doing the gravitational attraction math.

It's the same invalid math approach that, if you try it with the Sun and the Earth, will put the Moon's orbit out BEYOND the edge of Earth's gravity -- and if that were true, wouldn't the moon fly off onto an independent circuit of the Sun? Clue: it doesn't.

Do that math, and see how the results produce an obviously non-intuitive result. Earth still has a gravitational 'sphere of influence' wider than merely the edge of the mass-mass 'neutral point.

So does the Moon, in practice. So when people began throwing stuff out there, the old simple-minded mass-mass calculation was useless in predicting how the probes, which together with the Earth and Moon were moving freely through space, would move.

Hence the appearance of another value -- the boundary of the moon's sphere of influence.

It wasn't the moon's gravity that changed. It was the definition.

So, John, you are just decades out of date (thinking in pre Space Age terms), clueless about real spaceflight, proud of your ignorance, and obtusely resistent to anybody trying to explain it to you.

Well, to tell the truth, I like you that way. It makes debunking any other silliness you profess so much the easier.

And you know how well I get paid for THAT!


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