British Court's 71-Page Ruling On Da Vinci Code Has Hidden Code (Can ATS Crack it)

I wish I would have know a week ago, I bet ATS would have solved it first.

Anyway.

Smithy code with solution:
J a e i e x t o s t g p s a c g r e a m q w f k a d p m q z v(n)
J a c k i e f i s h e r w h o a r e y o u d r e a d n o u g h t

This is the ´Fibonacci sequence´ (yeah right) used:

1-1-2-2-4-7-12-20 1-1-2-2-4-7-12-20 1-1-2-2-4-7-12-20 1-1-2-2-4-7-12-20

(1=1=2=2=4 next 2+4+1=7 next 4+7+1=12 next 7+12+1=20)

Read the sequence with sidesteps as follows to jump around the alfabet:

1-same letter . .J = J
1-same letter . .a = a
2-back. . . . . . .e = c
2-back. . . . . . .i = k
4-forward . . . .e = i
7-forward . . . .x = e

12-forward . . . .t = f
20-forward . . . .o = i
1-same letter . .s = s
1-same letter . .t = h (sidestep 1, random one offset)
2-back. . . . . . .g = e
2-forward . . . .p = r (sidestep 2, random change of direction)

4-forward . . . .s = w
7-forward . . . .a = h
12-forward . . . .c = o

20-forward . . . .g = a
1-same letter . .r = r
1-same letter . .e = e

2-back . . . . . a = y
2-back . . . . . m = o
4-forward . . . q = u

7-forward . . . .w = d
12-forward . . . .f = r
20-forward . . . .k = e
1-same letter . .a = a
1-same letter . .d = d
2-back. . . . . . .p = n
2-forward . . . .m = o (sidestep 3, random change of direction)
4-forward . . . .q = u
12-forward . . . .v = h
20-forward . . . .n = t (sidestep 4, random missing letter)

Note the sequence error of character 10: the t in the word ´the´ was italic, but it needed to be the next character (h) to be in line with the sequence. Also the final character to complete the word dreadnought (t -20 == n) is missing.

Finally four sidesteps, of which two random. Too much guess work if you ask me.
This judge has way too much time on his hands!

Come to think of it, so have I.

HardToGet