First here is the ideal data for a collision with Asteroid 2006GY2
Bear with me here ive never plotted the trajectory of an Asteroid before.
But here I go...first and formost I used 11 points of reference for the asteroid....11 points over an 11 minute segement of observation. No reason why
i chose 11 thats just how many I chose...here are the points and thier corresponding angles...
=Convert_Decimal("45° 23' 40.50""") 45.39458333°
=Convert_Decimal("45° 23' 47.90""") 45.39663889°
=Convert_Decimal("45° 23' 56.10""") 45.39891667°
=Convert_Decimal("45° 23' 03.60""") 45.38433333°
=Convert_Decimal("45° 23' 40.10""") 45.39447222°
=Convert_Decimal("45° 23' 44.90""") 45.39580556°
=Convert_Decimal("45° 23' 51.40""") 45.39761111°
=Convert_Decimal("45° 23' 00.80""") 45.38355556°
=Convert_Decimal("45° 23' 12.00""") 45.38666667°
=Convert_Decimal("45° 23' 12.70""") 45.38686111°
=Convert_Decimal("45° 23' 25.90""") 45.39052778°
So from earth the object is coming at us at a Fourty Five Degree angle. The angles for optimum Earth Penetration...as far as I know any ways are
between 80-120°. Keep in mind I am a layman who is using only what he knows.I do not have a degree in Physics or Astrophysics for that matter. I just
took thier numbers and converted them into numbers WE could understand. Now to trully plot the trajectory of the Asteroid i need the intial velocity
from my point of observation...Velocity is distance divided by time. There was a degree change of 0.00405555°. So in 11 minutes the object had moved
by 0.00405555° which translates to between approx 0.4461105km and 0.31957734km or 44.61105m and 31.957734m. The reason for the difference in numbers
is because degrees dont translate well into linear numbers. At the equator a degree is 110km and at say 45degrees north its 78.8km. So the farther
down i convert the numbers the less accurate they are just sos ya know. Making the velocity of the object between approx 4.055555m/s and 2.90525m/s.
Making the speed of the object at around 14599.998meters/hour. So its cooking along quite quick. The object right now is approx 199549500km away from
us and it tends to stay that way. The objects node seperation from earth is 1.3303 AU away from Earth. Meaning that when its orbit isnt crossing ours
its that far away. Its orbit is 921.392 days...as opposed to our apprx 365 day orbit. As the object descends in its orbit meaning its coming back
around it gets closer to approx 1057500km away. The link i posted at the top of this has the ideal data for an earth collision if you dont understand
any of the terms feel free to Google them or U2U me if you cant find the information.
i will have the comet information later as it took me a while just to get this information. I hope I answered some of your questions in regards to
this asteroid. I do not have the software nessecary to give you an actual course projection of the asteroid. All i can do is take the observable from
earth data and transfer it into basic velocity and angle of either ascent or descent from our perspective.
Hope this helpes
El senor pom pom rides again
Whats important to note is that the eccentricity of this object is 0.493892 the max and min eccentricities for an earth impact are 0.5819 max and
0.4181min. So the eccentricity of it is right smack below the maximum. The asteroids inclination is also inbetween its too max's and mins for earth
strike. So yes it is possible that there could be a strike but i am not educated enough to come up with the raw data. Give me a new CPU a really nice
telescope and I might be able to...But seriously i didnt go to college for Physics. I did however do the best I could with the data I could find and I
hope this is better than nothing for you Agent T.
This asteroid might have some intersting mining options. The asteroid is moving quickly but its not moving as quickly as say a comet or an asteroid
formed from a planet destruction or being thrown by a larger asteroid. But thats a different topic. I will have the comet information just as soon as
I can find the nessecary data.
[edit on 24-4-2006 by Elsenorpompom]