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Originally posted by alienfy
x+1=1 (divide by x-1)
Originally posted by alienfy
1=2 I know it. My very super genious computer engineer teacher, Elwin, helped prove it.
Originally posted by muzzleflash
im not a math genious by any means
but i gave this equation he showed a try; and i respectfully disagree
Originally posted by DragonsDemesne
Off-topic: Arcane Demesne, love the name!
Originally posted by radiant
x=.999999...
10x=9.99999...
subtract the original equation
-x=-.999999...
9x=9.000000...
divde both sides by 9 and.......
x=1
Originally posted by radiant
x=.999999...
10x=9.99999...
subtract the original equation
-x=-.999999...
9x=9.000000...
divde both sides by 9 and.......
x=1
math is cool
(clarity)
[edit on 12-1-2006 by radiant]
[edit on 12-1-2006 by radiant]
Originally posted by Arcane Demesne
That one messes with my head, and it follows all the laws. Good job!
Originally posted by I_s_i_s
Originally posted by Arcane Demesne
That one messes with my head, and it follows all the laws. Good job!
Actually it doesnt...
Say you start small and take only 10 digits of 9's
x = .9999999999
10 x = 10 ( .9999999999) = 9.999999999 ( see there's only 9 digits after the decimal?)
When he subtracted again by x he's really doing this:
9.9999999990
- .9999999999
Originally posted by Arcane Demesne
Oh ok...I see. But I was under the impression that he meant .9999 with the bar over it (infinity 9's). Maybe not. I dunno.
Originally posted by I_s_i_s
Originally posted by Arcane Demesne
Oh ok...I see. But I was under the impression that he meant .9999 with the bar over it (infinity 9's). Maybe not. I dunno.
I'm under the same impression.
Bottom line you're subtracting .99999( infinite digits) from 9.9999(infinity - 1 digits) You'll end up with 8.9999999999999999999999999999999991
The last underlined 9 repeats