Originally posted by American Mad Man
Wow - this actually has my attention now - and I usually HATE math
OK so taking 10x - x = 9x, how did you get to 9x = 9?
As I recall, you can manipulate both sides, so long as you do the same to both (although I do recall there being exceptions to this rule).
If you were to devide by x, that would give you:
(10x-x)/x = 9x/x
this would then become 10x/x - x/x = 9x/x, each "x" cancels the other out (x/x = 1), thus:
10 - 1 = 9
so I don't think that does anything.
Your argument is flawed based on the mathematical Law of Equality.
10x - x = 9x.
This is true in the same way that 3x - x = 2x.
Example: Let x = 2
3(2) = 2 + 2 + 2 = 6
3x - x = 3(2) - 2 = 2 + 2 + 2 - 2 = 4
2x = 2 + 2 = 4
This relationship will be constant for any value of x.
Want another way to think of it? yx - x = (y-1)x.
To prove that, all you have to do is multiply through the right side.
Therefore, 10x - x = 9x.
QED ^.^
Edit to add some more information.
The reason we get 9x = 9 is simple as well. For reference, I'll write the entire proof here and put in some notes where applicable.
PROOF
---------
Let x = .999~
//We are declaring the variable x to be equal to .999~ where the nines repeat to infinity.
10x = 9.999~
//We multiply both sides by 10 which shifts the decimal one place to the right. It is important to note, however, that because the 9s repeat to
infinity, they continue to do so after the multiplication. In essence, the 9s following the decimal are equivalent in both .999~ and 9.999~ due to the
properties of infinitely repeating sets.
10x - x = 9x
//Now, as I described above, yx - x = (y-1)x through the Law of Equality.
9x = 9
//Now, we've shown that 10x = 9.999~ and x = .999~. If you subtract .999~ from 9.999~, you get 9. IE: 9.999~ - .999~ = 9
9x/9 = 9/9
//Divide both sides by 9.
x = 1
//Result shows that x = 1.
.999~ = 1
//Since we started out by setting x equal to .999~ repeating to infinity and have shown that x is equal to 1, by the Transitive Property, we have
proven that .999~ is equal to 1.
QED ^.^
[edit on 14-9-2009 by BriggsBU]