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originally posted by: SpaceBoyOnEarth
One kiloton has energy of 277777 WH
Lets imagine they drop 10 x 10 megaton nukes. It would be:
1 tnt nuke is = 4.184 gigajoules
4.184 gigajoules is 1162222 Wh (277777WH per gigajoule)
1 megaton is = 1000 kilotons. So
1 megaton = 277777000WH
10 megatons = 2777770000 WH
So 10 megatons nuke would be: 2.77 megawh.
10x 10 would be 27.7 megawatt hours.
Instead of dropping 10 nukes and having most energy just being deflected everywhere instead of melting the co2 ice,( because Musk wants any atmosphere he can get and he wants a thicker co2 atmosphere so hes proposing nukes) you go to Mars, install a:
Nuclear power plant.
A typical American nuclear power plant has the output of 1000-1500 MW
So in one day it producec: 24000MW.
So one 1000MW nuclear power plant will in one day of operation, same as 8664 x 10 megaton nukes.
originally posted by: Barcs
originally posted by: roadgravel
The atmosphere of Mars is about 100 times thinner than Earth's
LMAO. Another thread bites the dust.
A thorough understanding of thermodynamics is not a necessary requirement for the study of rocketry. As long as the temperature, molecular weight, of specific heat ratio of the exhaust products is known, the rocket equations can be solved. It is, however, often useful to be able to derive these quantities for one's self. In this article we provide an overview of the chemical thermodynamics applicable to rocket propulsion. It is assumed the reader has at least an elementary understanding of thermodynamics, as it is not our intent to fully explain the fundamentals.