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originally posted by: DutchMasterChief
a reply to: roadgravel
Correct, but this vid doesn't prove it wasn't shot in a plane during parabolic flight.
And it doesn't prove it was.
between the cuts the footage gets upto almost 1 minute long of zero gravity footage..
even if you consider that the ace pilot was able to put the aircraft into free fall after introducing zero g to the occupants to maintain zero g for the initial regular 25 seconds. by the time the remaining 30+ seconds of free fall zero g is over, the aircraft will be well well over mach 1.. and you expect the ace pilot to safely pull 2g-2.5g out of that without hitting the ground??
How did you get to a speed of mach 1?
because in a parabolic dive [ theres a hint in the name ] - the airfraft has to descend FASTER than the " weightless " crew
Again I ask, what is that mach 1 based on? Who says they weren't flying a bit above stall speed before the dive?
it wont be abit above stall speed as that would make their zero g time less..
(Contrary to popular misconception, the 0 g freefall phase of flight begins as the aircraft climbs, and does not occur solely as the aircraft descends. Although the aircraft has upward velocity during the initial 0 g phase, its acceleration is downward: the upward velocity is decreasing.)
and the aircraft will need to fall faster than free fall because inside there is no air resistance, so they would need to maintain zero g within the aircraft by flying faster than free fall downwards. if the aircraft was to fall at free fall speeds the occupants would be flat against one of the walls most likely the cockpit walls.
Parabolic flight generates freefall by following a trajectory wherein the acceleration of the aircraft cancels the acceleration due to gravity (Figure 1), along the aircraft vertical (z) axis. Essentially, if the aircraft and its occupants "fall" together at 9.81 m/s2, "0 g" is achieved, where there is no reaction force
p.s. the mach 1 is based on falling at 9.8m/s^2 for 30 seconds.
During such parabolic flight an aircraft flies a trajectory that provides freefall for up to 40 seconds
Between 1955 and 1958, a refined approach in the F-94 fighter allowed a variety of medical experiments to be performed during 30 to 40 seconds of freefall [3]. Between 1957 and 1959, the much larger C-131B cargo transport allowed simultaneous experiments on multiple subjects [4] and sufficient room for Mercury program astronauts to train (Figure 2), although this slower, propeller-driven aircraft could only produce parabolas with 10 to 15 seconds of freefall.
originally posted by: DutchMasterChief
During the upward part of the parabole that creates "zero gravity" there is actually deceleration, so it is flying relatively slow once it reaches the top of the parabole.
Again how could the plane be falling faster than its occupants if they are floating freely inside of it. They are obviously falling at the exact same speed, that's the whole point.
p.s. the mach 1 is based on falling at 9.8m/s^2 for 30 seconds.
Like I said before, it can be pushed to at least 40 seconds, they base this on a F-94.
Note that an F-94 has a lower top speed than an A300.
Where is this plane's hanger and what air field is it flown out of. Can't be a commercial airport or it wouldn't be secret after all these years.
Operating out of Bordeaux-Mérignac Airport, the aircraft usually flies up to a specially assigned air corridor above the Gulf of Gascogne. Flying level at about 6000 metres the weightlessness manoeuvre – known as a parabolic arc – begins when the aircraft is sent into a steep 45 degree climb on full engine thrust.
the problem with that is that 40 seconds can be reached by smaller more powerful aircraft.
this is after the parabola, since the parabola flightpath will only give about 25 seconds of apparent weightlessness.
the quote you have taken has broken apart the airplanes velocity into two parts, the horizontal velocity and the vertical. and is referring to the vertical part only.
originally posted by: DutchMasterChief
a reply to: choos
the problem with that is that 40 seconds can be reached by smaller more powerful aircraft.
Just a quick reply,the F-94 is not more powerful, since it is way smaller than an A300, yet it is slower....
this is after the parabola, since the parabola flightpath will only give about 25 seconds of apparent weightlessness.
But you used it as an argument refering to the actual "zero gravity" period. So that's some BS.
But you used it as an argument refering to the actual "zero gravity" period. So that's some BS.
originally posted by: DutchMasterChief
a reply to: choos
yep i meant power to weight ratio is higher.
No, otherwise it would be faster, ignoring aerodynamics. All that matters here is that the A300 is faster, period.
Comparing the F-94 to the A300 is like comparing a Corvette to the family station wagon.
The F-94, in aerodynamic terms was much more powerful than the A300, and could stay in free fall longer because it was designed that way.