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originally posted by: RobFox
If the molecular formula of Leucine is H02CCH(NH2)CH2CH(CH3)2, the molecular mass is 131.18 grams/mole. If 10 Leucines are joined together by a dehydration reaction to make a polypeptide, what would the molecular mass of the polypeptide equal?
N= 14g/mole, C=12g/mole, O=16g/mole, and H=1g/mole
Thank you for any help you can provide. I'm stumped.
originally posted by: stormcell
I've got the feeling that's someone's homework question.
dehydration = removal of water = removal of -COOH and replacement with -CO-NH, freeing one H2O.
You start with 10 moles of Leucine (10 x 131.18). You are going to lose 9 moles of -COOH's, but you gain 9 moles of -CO-NH, and 9 moles of H2O. Whatever all that adds up to,
10 x H02CCH(NH2)CH2CH(CH3)2,
- 9 x -COOH
+ 9 x -CO-NH
is your result